Gravesande, Willem Jacob 's, An essay on perspective

Table of figures

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[31] page 48.Plate 13.Fig. 32.V S R L P B D Q T M I F A E Y C G O H Z N
[32] page 52.Plate. 14.Fig. 34D C F G A B H L E
[33] Fig. 33S X 8 1 h 6 g 3 z q 9 m 2 4 m a 5 Y
[34] Fig. 35O M D P T Q R m p q B A S C
[35] page 56.Plate. 15F H O Z D G
[36] Fig. 36T N M L a R Q E I A C P B
[37] Fig. 37F S V T I E M A N X P C B
[38] page 58.Plate. 16Fig. 39Fig. 38F Q O p l r s 1 2 3 4 G
[39] page 60.Plate. 17F V
[40] Fig. 40c θ b e a F G H I K L A B E C D
[41] page 64Plate. 18.d v
[42] Fig. 41E b a G F H C B A D
[43] Fig. 42G Q A M I S E H T B L Z F P a X Y N C D R O
[44] page 68Plate. 19Fig. 43B D E a G H I C F L
[45] Fig. 44O V X S H I T
[46] Fig. 45Q F V X S a H B C D E L M P T A
[47] page 72Plate. 20Fig. 46V I X a E M P A T
[48] Fig. 47V F X a Q G H D N A T R
[49] Page 34.Plate. 21Fig. 48F O D X S b a G N A E T B P C
[50] Fig. 49H F O D G X a M N L R Q
[51] Page 36Plate 22Fig. 50O R E G N S M
[52] Fig. 51I H T a X
[53] Fig. 52C D X I H G a F E L b T
[54] Fig. 53H I F T x d X L B C
[55] page 64.Plate 23.Fig. 54O M P Q t A X x Q R N
[56] Fig. 55G F b T L a
[57] Fig. 56I F a X b E T C P
[58] page 66.Plate. 24.Fig. 57E A Z C P B
[59] Fig. 58F O D I a b
[60] Fig. 59F E Z C A B
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            for then, what is on the Right, will appear on
              <lb/>
            the Left.</s>
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          <p>
            <s xml:id="echoid-s502" xml:space="preserve">Therefore, I lay my Perſpective Plane upon
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            the Geometrical Plane; </s>
            <s xml:id="echoid-s503" xml:space="preserve">ſo that it be between
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            the Horizontal Plane, and the Figures requir’d
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            to be thrown into Perſpective.</s>
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        <div xml:id="echoid-div55" type="section" level="1" n="27">
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            <emph style="sc">Problem</emph>
          I.</head>
          <p style="it">
            <s xml:id="echoid-s505" xml:space="preserve">22. </s>
            <s xml:id="echoid-s506" xml:space="preserve">To find the Appearance of a Point, which is in
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            the Geometrical Plane.</s>
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            <s xml:id="echoid-s508" xml:space="preserve">Let Z be the Geometrical Plane, I E the Baſe
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              <note position="left" xlink:label="note-0036-01" xlink:href="note-0036-01a" xml:space="preserve">Fig. 7.</note>
            Line, D V the Horizontal Line, V the Point
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            of Sight, D one of the Points of Diſtance, and
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            A the given Point.</s>
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        <div xml:id="echoid-div57" type="section" level="1" n="28">
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            <emph style="sc">Operation</emph>
          .</head>
          <p>
            <s xml:id="echoid-s510" xml:space="preserve">From the Point A, let fall the Perpendicular
              <lb/>
            A B upon the Baſe Line; </s>
            <s xml:id="echoid-s511" xml:space="preserve">and from the Point of
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            Concurrence B, draw the Line B V to the Point
              <lb/>
            of Sight; </s>
            <s xml:id="echoid-s512" xml:space="preserve">then aſſume B E in the Baſe Line
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            equal to B A, and from the Point E draw the
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            Line E D to the Point of Diſtance D: </s>
            <s xml:id="echoid-s513" xml:space="preserve">And the
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            Point (a), the Interſection of B V and E D, is
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            the Repreſentation ſought.</s>
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        <div xml:id="echoid-div58" type="section" level="1" n="29">
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            <emph style="sc">Demonstration</emph>
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          <p>
            <s xml:id="echoid-s515" xml:space="preserve">23. </s>
            <s xml:id="echoid-s516" xml:space="preserve">The Appearance of the Line A B, is a Part of the Line B V. </s>
            <s xml:id="echoid-s517" xml:space="preserve">Now, if we conceive a Line
              <lb/>
              <note symbol="*" position="left" xlink:label="note-0036-02" xlink:href="note-0036-02a" xml:space="preserve">16.</note>
            iſſuing from the Eye towards the Point D, and
              <lb/>
            another from the Point A towards the Point E;
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            </s>
            <s xml:id="echoid-s518" xml:space="preserve">theſe two Lines will be parallel, becauſe they
              <lb/>
            are in parallel Planes, aud each make half a
              <lb/>
            right Angle with the Perſpective Plane; </s>
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