Clavius, Christoph, Geometria practica

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397369LIBER OCTAVVS.
PROBL. 24. PROPOS. 38.
DATO parallelepipedo rectangulo cubum æqualem deſcribere.
Si parallelepipedum non habet baſem quadratam, fiat eius baſi 5514. ſecundi.289[Figure 289] tum æquale BCD, ſupra quod erigatur parallelepi-
pedum
rectangulum eiuſdem altitudinis A B, cum
parallelepipedo
dato, quod æquale erit dato 662. coroll. 7.
duodec
.
rallelepipedo.
Huic ergo cubum æqualem con-
ſtruemus
hacarte.
Inter BC, latus quadrati BD, &
A
B, altitudinem parallelepipedi, inueniantur duæ
med@æ
prop@rtionales EF, H:
ita vt ſit BC, ad EF,
quemadmodum
EF, ad H, &
H, ad A B. Et ſuper
EF
, propinquiorem lateri B C, conſtruatur cubus EFG.
qui 77Lemma 18.
ſexti
hui{us}.
ABCD, æqualis erit.

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