Cavalieri, Buonaventura
,
Geometria indivisibilibvs continvorvm : noua quadam ratione promota
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GEOMETRIÆ
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ſimilia, & </
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s
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">ex ratione, quæ in huius Theorematis ſupradi-
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ctis caſibusinter illa duorectangula primò loco expoſita
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fuit.</
s
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<
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<
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<
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">Sint aſſumptę quęcunq; </
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<
s
xml:id
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echoid-s9825
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xml:space
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">hyperbolę, BAD, HMQ, circa axes,
<
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vel diametros, AC, MP, circa quas ſint quoq; </
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<
s
xml:id
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echoid-s9826
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xml:space
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">triangula, BAD, H
<
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MQ, & </
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<
s
xml:id
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echoid-s9827
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xml:space
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">in baſibus, BD, HQ, latus autem tranſuerſum hyperbolę,
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BAD, ſit, GA, cuius ſexquialtera, VA; </
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<
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xml:space
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">& </
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<
s
xml:id
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echoid-s9829
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xml:space
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">larus tranſuerſum hy-
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perbolę, HMQ, ſit, MX, cuius ſexquialtera, MR, ſint autem ex-
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poſitæ duæ vtcunque rectæ lineæ, FY, EN. </
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<
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">Dico omnia qua-
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drata hyperbolę, BAD, regula, BD, ad omnia quadrata hyper.
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<
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fig-0402-01
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xlink:href
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fig-0402-01a
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number
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274
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<
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0402-01
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xlink:href
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http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/05TCTFNR/figures/0402-01
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</
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perbolę, HMQ, regu-
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la, HQ, habereratio-
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nem compoſitã ex ea,
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quam habet rectangu-
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lum ſub, VC, XP, adre-
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ctangulum ſub RP, C
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G, & </
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<
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xml:space
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">ex ea, quam ha-
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bet parallelepipedum
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ſub altitudinehyperbo-
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lę, BAD, & </
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<
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xml:space
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">ſub qua-
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drato, BD, ad paralle-
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lepipedum ſub altitu-
<
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dine hyperbolę, HMQ,
<
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baſi quadrato, HQ;
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</
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<
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xml:space
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">quod oſtendemus ad
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modum Propoſ. </
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<
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<
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">Si
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verò comparentur om-
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nia quadrata hyperbolæ, BAD, ad omnia rectangula hyperbolæ,
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HMQ, ſimilia rectangulo ſub, HQ, EN, oſtendemus illa ad hæc
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habere rationem compoſitam ex ratione primò dicta inter illa re-
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ctangula, & </
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<
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xml:space
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">ex ratione parallelepipedi ſub altitud ne hyperpolæ,
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BAD, baſiquad ato, BD, ad parallelepipedum ſub altitudine hy-
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perbolæ, HMQ, baſi rectangulo ſub, HQ, EN; </
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<
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">hocq; </
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<
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">oſtende-
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mus iuxta methodum Propol. </
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<
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rentur omnia rectangula hyperbolæ, BAD, ſimilia rectangulo ſub,
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BD, FY, ad omnia rectangula hy perbolæ, HMQ, ſimilia rectan-
<
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gulo ſub, HQ, EN, oſten demus propoſitum de his hoc pacto: </
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<
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">Nã
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omnia rectangula hyperbolæ, BAD, ſimilia rectangulo ſub, BD,
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FY, ad omnia quadrata eiuſdem, BAD, ſunt vt rectangulum ſub,
<
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BD, FY, ad?</
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<
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