DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N106DF">
            <p id="id.2.1.181.0.0" type="main">
              <s id="id.2.1.181.13.0">
                <pb xlink:href="037/01/042.jpg"/>
                <emph type="italics"/>
              ſtarà piu ſopra il centro C, che in K. </s>
              <s id="id.2.1.181.14.0">Adunque il peſo poſto in K ſarà piu
                <lb/>
              graue, che in D, & in D, che in L. </s>
              <s id="N1163D">& con la medeſima ragione in tutto, pero­
                <lb/>
              che KN è minore di HO, ſarà l'angolo CKS maggiore dell'angolo CHS.
                <lb/>
              </s>
              <s id="id.2.1.181.15.0">Per laqual coſa il peſo posto in H ſtarà piu ſopra il centro C, che in
                <emph.end type="italics"/>
              K;
                <emph type="italics"/>
              & in que­
                <lb/>
              ſta maniera ſi mostrerà, che douunque ſia il peſo nella circonferenza FDG, manco
                <lb/>
              starà ſopra il centro quando ſarà poſto in K, che in altro ſito: & quanto piu da
                <lb/>
              preſſo egli ſarà ad F, ouero à G piu ſtarà ſopra. </s>
              <s id="id.2.1.181.16.0">Dopo percioche l'angolo CKS
                <lb/>
              è maggiore del CDS, & CDK è eguale à CKH: ſarà il reſtante SKH mi­
                <lb/>
              nore del reſtante SDK. </s>
              <s id="id.2.1.181.17.0">Per laqual coſa la circonferenza KH ſarà piu da preſſo
                <lb/>
              al mouimento naturale
                <lb/>
              diritto del peſo poſto in
                <lb/>
              K ſciolto, cioè alla li­
                <lb/>
              nea KS, che la circon
                <lb/>
              ferenza DK al moui­
                <lb/>
              mento DS. </s>
              <s id="id.2.1.181.18.0">& perciò
                <lb/>
              la linea CD ſa piu reſi
                <lb/>
              ſtenza al peſo poſto in D
                <lb/>
              che la CK al peſo meſ­
                <lb/>
              ſo in
                <emph.end type="italics"/>
              K. </s>
              <s id="N11675">
                <emph type="italics"/>
              & per queſta
                <lb/>
              ragione ſi moſtrera l'an­
                <lb/>
              golo SHG eſſer mag­
                <lb/>
              giore dello SKH; &
                <lb/>
              per conſequente la linea
                <lb/>
              CH ſare piu reſiſtenza
                <lb/>
              al peſo poſto in H, che
                <lb/>
              CK al peſo meſſo in K.
                <lb/>
              </s>
              <s id="id.2.1.181.19.0">Similmente dimoſtreraſſi
                <lb/>
              che la linea CL piu ſo­
                <lb/>
              ſtenterà il peſo, che CD:
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.042.1.jpg" xlink:href="037/01/042/1.jpg" number="25"/>
                <lb/>
                <emph type="italics"/>
              & per le, cagioni iſteſſe ſi prouerà, che il peſo meſſo in K grauerà meno ſopra la li­
                <lb/>
              nea CK, che in qual ſi voglia altro ſito della circonferenza FDG: & quanto
                <lb/>
              piu da preſſo ſarà ad F, ouero à G, manco grauerà. </s>
              <s id="id.2.1.181.20.0">dunque piu graue ſara in K,
                <lb/>
              che in altro ſito: & ſarà meno graue quanto piu da preſſo ſtara ad F, ouero a G.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.184.0.0" type="margin">
              <s id="id.2.1.184.1.0">
                <margin.target id="note39"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              35.
                <emph type="italics"/>
              del terzo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.185.0.0" type="margin">
              <s id="id.2.1.185.1.0">
                <margin.target id="note40"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              16.
                <emph type="italics"/>
              del ſesto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.186.0.0" type="margin">
              <s id="id.2.1.186.1.0">
                <margin.target id="note41"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              7.
                <emph type="italics"/>
              del terzo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.187.0.0" type="margin">
              <s id="id.2.1.187.1.0">
                <margin.target id="note42"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              25.
                <emph type="italics"/>
              del quinte.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.188.0.0" type="margin">
              <s id="id.2.1.188.1.0">
                <margin.target id="note43"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              25.
                <emph type="italics"/>
              del primo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.189.0.0" type="main">
              <s id="id.2.1.189.1.0">
                <emph type="italics"/>
              Se in fine il centro C foſſe nel centro del mondo, egli è manifeſto, che il peſo poſto doue
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note44"/>
                <emph type="italics"/>
              ſi voglia ſtarà fermo. </s>
              <s id="id.2.1.189.2.0">Come posto il peſo in D la linea CD ſoſterrà tutto il peſo,
                <lb/>
              per eſſer a piombo dell'orizonte di eſſo peſo poſto in D. </s>
              <s id="id.2.1.189.3.0">Dunque ſtarà fermo
                <lb/>
              il peſo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.190.0.0" type="margin">
              <s id="id.2.1.190.1.0">
                <margin.target id="note44"/>
                <emph type="italics"/>
              Per la prima di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.191.0.0" type="main">
              <s id="id.2.1.191.1.0">
                <emph type="italics"/>
              Hor percioche nelle coſe, che fin qui ſono ſtate dimostrate non habbiamo fatto mentio­
                <lb/>
              ne alcuna della grauezza del braccio della bilancia, però ſe vorremo anco conſidera­
                <lb/>
              re la grauezza del detto braccio, ſi potrà ritrouare il centro della grauezza della ma
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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