Archimedes
,
Natation of bodies
,
1662
Text
Text Image
XML
Document information
None
Concordance
Figures
Thumbnails
Page concordance
<
1 - 30
31 - 60
61 - 68
>
Scan
Original
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
<
1 - 30
31 - 60
61 - 68
>
page
|<
<
of 68
>
>|
<
archimedes
>
<
text
>
<
body
>
<
chap
>
<
p
type
="
main
">
<
s
>
<
pb
xlink:href
="
073/01/046.jpg
"
pagenum
="
376
"/>
and F leſs than B R. </
s
>
<
s
>Let R
<
foreign
lang
="
grc
">Ψ</
foreign
>
be equall to F; and draw
<
foreign
lang
="
grc
">Ψ</
foreign
>
E
<
lb
/>
perpendicular to B D; which let be in power the half of that
<
lb
/>
which the Lines K R and
<
foreign
lang
="
grc
">Ψ</
foreign
>
B containeth; and draw a Line from
<
lb
/>
B to E: I ſay that the Portion demitted into the Liquid, ſo as that
<
lb
/>
its Baſe be wholly within the Liquid, ſhall ſo ſtand, as that its Axis
<
lb
/>
do make an Angle with the Liquids Surface, equall to the Angle B.
<
lb
/>
</
s
>
<
s
>For let the
<
emph
type
="
italics
"/>
P
<
emph.end
type
="
italics
"/>
ortion be demitted into the Liquid, as hath been ſaid;
<
lb
/>
and let the Axis not make an Angle with the Liquids Surface, equall
<
lb
/>
to B, but firſt a greater: and the ſame being cut thorow the Axis
<
lb
/>
by a Plane erect unto the Surface of the Liquid, let the Section of
<
lb
/>
the Portion be A P O L, the Section of a Rightangled Cone; the
<
lb
/>
Section of the Surface of the Liquid
<
foreign
lang
="
grc
">Γ</
foreign
>
I; and the Axis of the
<
lb
/>
Portion and Diameter of the Section N O; which let be cut in
<
lb
/>
the Points
<
foreign
lang
="
grc
">ω</
foreign
>
and T, as before: and draw Y P, parallelto
<
foreign
lang
="
grc
">Γ</
foreign
>
I, and
<
lb
/>
touching the Section in P, and MP parallel to N O, and P S perpen
<
lb
/>
dicular to the Axis. </
s
>
<
s
>And becauſe now that the Axis of the Portion
<
lb
/>
maketh an
<
emph
type
="
italics
"/>
A
<
emph.end
type
="
italics
"/>
ngle with the Liquids Surface greater than the Angle
<
lb
/>
B, the Angle S Y P ſhall alſo be greater than the Angle B: And,
<
lb
/>
therefore, the Square P S hath greater proportion to the Square
<
lb
/>
<
arrow.to.target
n
="
marg1281
"/>
<
lb
/>
S Y, than the Square
<
foreign
lang
="
grc
">Ψ</
foreign
>
E hath to the Square
<
foreign
lang
="
grc
">Ψ</
foreign
>
B: And, for that
<
lb
/>
cauſe, K R hath greater proportion to S Y, than the half of K R
<
lb
/>
hath to
<
foreign
lang
="
grc
">Ψ</
foreign
>
B: Therefore, S Y is leſs than the double of
<
foreign
lang
="
grc
">Ψ</
foreign
>
B; and
<
lb
/>
<
arrow.to.target
n
="
marg1282
"/>
<
lb
/>
S O leſs than
<
foreign
lang
="
grc
">ψ</
foreign
>
B:
<
emph
type
="
italics
"/>
A
<
emph.end
type
="
italics
"/>
nd, therefore, S
<
foreign
lang
="
grc
">ω</
foreign
>
is greater than R
<
foreign
lang
="
grc
">ψ</
foreign
>
; and
<
lb
/>
<
arrow.to.target
n
="
marg1283
"/>
<
lb
/>
P H greater than F.
<
emph
type
="
italics
"/>
A
<
emph.end
type
="
italics
"/>
nd, becauſe that the
<
emph
type
="
italics
"/>
P
<
emph.end
type
="
italics
"/>
ortion hath the
<
lb
/>
ſame proportion in Gravity unto the Liquid, that the Exceſs by
<
lb
/>
which the Square B D, is greater than the Square F Q, hath unto
<
lb
/>
the Square B D; and that as the Portion is in proportion to the
<
lb
/>
Liquid in Gravity, ſo is the part thereof ſubmerged unto the whole
<
lb
/>
Portion; It followeth that the part ſubmerged, hath the ſame
<
lb
/>
proportion to the whole
<
emph
type
="
italics
"/>
P
<
emph.end
type
="
italics
"/>
ortion, that the Exceſs by which the
<
lb
/>
Square B D is greater than the Square F Q hath unto the Square
<
lb
/>
B D:
<
emph
type
="
italics
"/>
A
<
emph.end
type
="
italics
"/>
nd, therefore, the whole
<
emph
type
="
italics
"/>
P
<
emph.end
type
="
italics
"/>
ortion ſhall have the ſame propor
<
lb
/>
<
arrow.to.target
n
="
marg1284
"/>
<
lb
/>
tion to that part which is above the
<
lb
/>
<
figure
id
="
id.073.01.046.1.jpg
"
xlink:href
="
073/01/046/1.jpg
"
number
="
45
"/>
<
lb
/>
Liquid, that the Square B D hath to
<
lb
/>
the Square F Q: But as the whole
<
lb
/>
Portion is to that part which is above
<
lb
/>
the Liquid, ſo is the Square N O unto
<
lb
/>
the Square P M: Therefore, P M
<
lb
/>
ſhall be equall to F Q: But it
<
lb
/>
hath been demonſtrated, that P H is
<
lb
/>
greater than F. And, therefore,
<
lb
/>
MH ſhall be leſs than
<
expan
abbr
="
q;
">que</
expan
>
and P H
<
lb
/>
greater than double of H M. </
s
>
<
s
>Let
<
lb
/>
therefore, P Z be double to Z M: </
s
>
</
p
>
</
chap
>
</
body
>
</
text
>
</
archimedes
>