Cavalieri, Buonaventura
,
Geometria indivisibilibvs continvorvm : noua quadam ratione promota
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A, ad parallelepipe-
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dum ſub compoſita
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ex ſexquialteraeiuſ-
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dem tranſuerſi late-
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ris, &</
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drato, KA. </
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<
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verò, DAF, ad co-
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num, MAI, vt cu-
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bus, EA, ad cubum,
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AK.</
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xml:space
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Cor. gen.
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34. l. 2.</
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tur demptum à cy-
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lindro, BF, hæmi-
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ſphærium, vel hæ-
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miſphæroides, DVATF. </
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<
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">Igitur per demonſtrata patet reliquum
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cylindri ab abſciſſam ab eo portionem per ductum planum eſſe, vt
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">Coroll. 5.
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34. l. 3.</
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cubus, AE, eſt ad cubum, EK. </
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<
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lico ab eodem cylindro; </
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">reliquum cylindri ab abſciſſam portionẽ
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erit, vt quadratum, AE, ad quadratum, EK. </
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<
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">Coroll. 9.
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51. l. 4.</
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noide hyperbolico ab eodem cylindro, reliquum cylindri ad ab-
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ſciſſam portionem erit, vt parallelepipedum ſub compoſita ex
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ſexquialtera tranſuerſi lateris, & </
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drato eiuſdem axis, ad parallelepipedum ſub compoſita ex ſex-
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30. l. 5.</
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quialtera eiuſdem tranſuerſi lateris, & </
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& </
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dempto cono, DAF, à cylindro, BF, reſiduum cylindri ad abſciſsã
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portionem erit, vt cubus, AE, ad parallelepipedum ſub ſexquialte-
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<
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xlink:label
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l. 1.</
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ra, kE, & </
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<
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lindrus, BF, ad reliquum cylindri, CF, dempto fruſto coni, DMIF,
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gener. 34.
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l. 2.</
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habet rationem compoſitam ex ea, quam habet cylindrus, BF, ad
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cylindrum, CF, ideſt ex ea, quam habet, AE, ad, EK, & </
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L. Coroll.
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4. gener.
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34. l. 2.</
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ne cylindri, CF, ad reliquum, dempto à cylindro, CF, fruſto, DM
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IF, quæ eſt ea, quam habet quadratum, DE, ad rectangulum, CM
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K, cum {2/3}. </
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<
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KA, cum {2/3}. </
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<
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">quadrati, EK, eſt autem reliquum cylindri, BF, dem-
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pto cono, DAF, {2/3}. </
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<
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">eiuſdem cylindri, ergo reliquum cylindri, BF,
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dempto cono, DAF, ad reliquum cylindri, CF, dempto fruſto, D
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MIF, erit in ratione compoſita ex ea, quam habẽt {2/3}. </
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ideſt, AE, ad ſexquialteram, EK, & </
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<
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<
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Cor. gen.
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34. l. 2.</
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lum, AKE, cum {2/3}. </
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<
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rationem cubi, AE, ad parallelepipedum ſub ſexquialtera, Ek, &</
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