Huygens, Christiaan, Christiani Hugenii opera varia; Bd. 2: Opera geometrica. Opera astronomica. Varia de optica

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[181] Fig. 3.E C D A * B
[182] Fig. 4.P Q O N M L * C R
[183] Fig. 5.C * V S X T Y
[184] Fig. 6.
[185] Fig. 7.
[186] Pag. 580.TAB. L.Fig. 2.R ♈ L D I T A N ♋ H G E P F K C Q O B M S
[187] Fig. 3.
[188] Fig. 4.N Q F C P L E A M H O D f
[189] Fig. 1.B A
[Figure 190]
[Figure 191]
[192] Pag. 626.TAB. LI.Fig. 1.F E D V S 30 20 10 C L G R H K P A M Z I O X B
[193] Fig. 2.L K O R E H N I S D G B C
[194] Fig. 3.A 16 15 14 13 12 11 10 9 B 8 7 6 5 4 3 2 1
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525759VARIA DE OPTICA.
II.
CONSTRUCTIO PROBLEMATIS OPTICI.
Propoſitio 39 Libri v. Alhazeni, & 22 lib. VI.
Vitellionis.
Puncta B, C, & circulus E K, cujus centrum eſt A,
11TAB. LVI.
fig. 1.
data ſunt in eodem plano;
inveniendum eſt pun-
ctum K in peripheria circuli, ita ut lineæ B K, C K
faciant cum linea A K angulos inter ſe æquales.
DUctis A B, A C; fiat A C, A F: : A F, A Q; & A B,
A E:
: A E, A P: ſint etiam A P, & A Q, bifariam di-
viſæ in R &
S; in angulo B A C ſint perſecta parallelo-
gramma P A Q H &
A R Z S. In R Z producta ſumantur
Z Y &
Z X, utraque æqualis lineæ quæ poteſt differentiam
inter quadrata Q S &
Z S: fiat X V æqualis X Y & paral-
lela A B;
& lateribus X V & X Y deſcribatur hyperbola,
quæ tranſibit per puncta Q &
H, uti patet per conſtructio-
nem;
hyperbola hæc Q X H occurret circulo in puncto K,
quod quæritur.
Ductis K O & KI parallelis A C & A B, quarum K I
occurrit Y X in puncto D.
Ob hyperbolam rectangulum
Y D X æquale eſt quadrato K D ordinatæ, vel quadrato O R;
& rectangulum Y T X æquale eſt quadrato H T, vel quadra-
to P R;
& demto a rectangulo Y T X, rectangulum Y D X
&
a quadrato P R, quadratum O R, ſupererit rectangu-
lum R D T vel A I Q, quod æquale erit rectangulo A O P.

P O ergo eſt ad A I, vel O K ipſi æqualem, ut Q I ad
A O, vel I K;
& ductis lineis K P, K Q triangula K O P,
K I Q erunt ſimilia &
ideo æquiangula; idcirco anguli
A P K, A Q K, qui iidem ſunt, vel ſupplementa angulorum
æqualium O P K, I Q K erunt inter ſe æquales;
ſed per con-
ſtructionem A B, A E vel A K, :
: A K vel A E, A P;
ideo duo triangula B A K, K A P ſunt ſimilia, &
ob ean-
dem cauſam duo triangula C A K, K A Q, ſunt etiam ſi-
milia;
ideo angulus B K A eſt æqualis angulo A P K, &

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