Clavius, Christoph
,
Gnomonices libri octo, in quibus non solum horologiorum solariu[m], sed aliarum quo[quam] rerum, quae ex gnomonis umbra cognosci possunt, descriptiones geometricè demonstrantur
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erit B M, circunferentia horaria. </
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<
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xml:space
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ticalis ſecat, vt centro, interuallo verò n K, in Meridiano ſumatur beneficio circini punctum P,
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erit A P, circunferentia
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deſcenſiua. </
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<
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xml:space
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ius rei eſt, quòd ducta
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recta f L, perpendicula
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ris eſt ad rectam ELY:
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</
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<
s
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xml:space
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">ducta autẽ recta MLN,
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ad B D, perpẽdicularis
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eſt; </
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<
s
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xml:space
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">& </
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<
s
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xml:space
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">recta P L O, ad
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<
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xlink:label
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xml:space
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A C, vt mox demon-
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ſtrabimus. </
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<
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xml:space
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">Cum ergo
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prius per has perpendi
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culares L f, M L N,
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P L O, inuentę ſint tres
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dictæ circunferentię, vt
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in ſequenti cap. </
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<
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demus, eædem etiam
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inuentæ erunt per pun-
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cta f, M, P, in Meridia
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<
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no accepta, vt diximus.
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</
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<
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xml:space
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E L Y, perpendicularẽ
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eſſe, ita probabimus. </
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Ducta recta E f, quoniã
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duo latera K L, L E, triã
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guli K L E, ęqualia ſunt
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duobus lateribus f L,
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L E, trianguli f L E, (quòd interuallum L f, interuallo L K, ſumptum eſt æquale) eſtq́ue baſis k E,
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baſi f E, ęqualis, (quòd vtraque ſit ſphęrę ſemidiameter) erit angulus k L E, angulo f L E, ęqualis. </
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<
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xlink:label
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xml:space
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">8. primi.</
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Cum ergo k L E, rectus ſit, vt
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paulo ante oſtendimus, erit & </
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f L E, rectus, ideoq́; </
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<
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<
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">, ad ELY,
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perpendicularis erit. </
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<
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etiam probabimus, ſi ex L, duca
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tur ad E L Y, perpendicularis
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L f, eam æqualẽ eſſe rectæ L K.
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</
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<
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xml:space
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">Cũ enim duo quadrata ex E k,
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E f, æqualia ſint, erunt duo qua-
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drata ex E L, L K, duobus qua-
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dratis ex E L, L f, æqualia Abla
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to ergo communi quadrato re-
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ctæ E L, reliqua erunt quadra-
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ta rectarum L K, L f, æqualia,
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proptereaq́ue & </
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<
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xml:space
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">rectæ L K, L f,
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æquales erunt. </
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<
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confirmabimus. </
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<
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cta Y E, vſque ad Z. </
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<
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igitur K L, ad diametrum paral
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leli a b, perpendicularis media
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propottionalis eſt inter ſegmen
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ta a L, Lb, ex ſcholio propoſ. </
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<
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<
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<
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K L, æquale rectangulo ſub a L,
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<
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Lb, contento. </
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<
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">Eodem modo, erit fL, perpendicularis ducta ad Y Z, media proportionalis inter
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ſegmenta Y L, L Z, atque adeo quadratum ex fL, rectangulo ſub γ L, L Z, æquale. </
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<
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xml:space
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ctangula ſuba L, L b, & </
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<
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<
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">quadrata ex K L, f L, æqualia, ideoq́ue
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& </
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<
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<
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<
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">AT vero rectas M L N, P L O, ad rectas B D, A C, perpendiculares eſſe, facile comprobabi-
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mus, ſi prius demonſtremus, ſi per L, ducantur rectæ M L N, P L O, ad B D, A C, perpendicula-
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res, coniungaturq́ue rectæ d M, d K, & </
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<
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xml:space
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<
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