Angeli, Stefano degli, Della gravita' dell' aria e fluidi : esercitata principalmente nelli loro homogenei

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            DFE, ABC. </s>
            <s xml:id="echoid-s1729" xml:space="preserve">Dico adunque, che collocato nell’ acqua per-
              <lb/>
            pendicolarmente, cioè la baſe ABC, orizontale, queſto non
              <lb/>
            ſeguirà a muouerſi così, ma de neceſſità ſi voltarà nel taglio
              <lb/>
            DA. </s>
            <s xml:id="echoid-s1730" xml:space="preserve">Perche ſe intenderemo’la LM, che congiunga li centri
              <lb/>
            di grauità delli due triangoli oppoſti, nel mezzo di eſſa ſarà
              <lb/>
            il centro di grauità del Priſma. </s>
            <s xml:id="echoid-s1731" xml:space="preserve">Il quale ſe s’intenderà diuiſo
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            con il piano HI, parallelo all’ EB, lo diuiderà in due par-
              <lb/>
            ti di momenti eguali, ma non eguali di mole; </s>
            <s xml:id="echoid-s1732" xml:space="preserve">perche il Priſ-
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            ma del quale è baſe il Trapezio BIKC, al priſma del quale è
              <lb/>
            baſe il triangolo A K I, ha la medema proportione, che hà
              <lb/>
              <figure xlink:label="fig-00056-01" xlink:href="fig-00056-01a" number="13">
                <image file="00056-01" xlink:href="http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/9EXVCG1R/figures/00056-01"/>
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            il trapezio al triangolo. </s>
            <s xml:id="echoid-s1733" xml:space="preserve">Ma quello a queſto ha la proportio-
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            ne, che ha 5. </s>
            <s xml:id="echoid-s1734" xml:space="preserve">à 4. </s>
            <s xml:id="echoid-s1735" xml:space="preserve">perche M, centro de grauità del triangolo
              <lb/>
            ABC, diuide l’aſſe PA, di modo, che PA, ſia ſeſquialtera di
              <lb/>
            AM; </s>
            <s xml:id="echoid-s1736" xml:space="preserve">& </s>
            <s xml:id="echoid-s1737" xml:space="preserve">il trapezio al triangolo hà la proportione, che ha
              <lb/>
            l’ecceſſo del quadrato P A, ſopra il quadrato AM, al mede-
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            mo; </s>
            <s xml:id="echoid-s1738" xml:space="preserve">che è poi quella, che ha 5. </s>
            <s xml:id="echoid-s1739" xml:space="preserve">a 4.</s>
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