<s id="A18-1.04.01">[4] On the different circles.Now let the circles be unequal; and let their centers lie on the two points <a> and <b>, further let the larger of the two circles be the one whose center lies on point <a>, then the order with these circles will not be perfect as with equal circles.</s>
<s id="A18-1.04.02">Let us now assume two points that we let rotate from point <e> and let us make, to pose an example, the diameter <ge> twice the size of the diameter <ed>, then the arc <ezg> will be twice the arc <ehd>, for Archimedes has already proven this.</s>
<s id="A18-1.04.03">Then in the same time that point <e> in its motion towards <g> runs along the arc <ez>, point <e> will run in the opposite direction along the arc <ehd>.</s>
<s id="A18-1.04.04">Further in the same time that point <e>, starting at <z>, runs along the arc <zg>, point <e> will, starting at <d>, run along the arc <dke> and reach point <e>.</s>
<s id="A18-1.04.05">Thus the point that runs along the arc <ehdke> will one time make the opposite motion to the point that runs along the arc <ezg>, the other time be equal to it.</s>
<s id="A18-1.04.06">Further, in the same time that point <g> runs through the arc <gqe>, point <e> runs through the arc <ehdke>, partially in the same, partially in the opposite direction as <g>.</s>
<s id="A18-1.04.07">If now the one arc is three times as large as the other one, or in any other relation to it, then we shall show that the moving points are moving partially in the same, partially in the opposite direction.</s>
