Stelliola, Niccol� Antonio, De gli elementi mechanici, 1597

Table of figures

< >
[Figure 1]
[Figure 2]
[Figure 3]
[Figure 4]
[Figure 5]
[Figure 6]
[Figure 7]
[Figure 8]
[Figure 9]
[Figure 10]
[Figure 11]
[Figure 12]
[Figure 13]
[Figure 14]
[Figure 15]
[Figure 16]
[Figure 17]
[Figure 18]
[Figure 19]
[Figure 20]
[Figure 21]
[Figure 22]
[Figure 23]
[Figure 24]
[Figure 25]
[Figure 26]
[Figure 27]
[Figure 28]
[Figure 29]
[Figure 30]
< >
page |< < of 69 > >|
    <archimedes>
      <text>
        <body>
          <chap id="N111A4">
            <pb xlink:href="041/01/061.jpg" pagenum="60"/>
            <p id="N11292" type="head">
              <s id="N11294">
                <emph type="italics"/>
              Dimostratione.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N1129A" type="main">
              <s id="N1129C">
                <emph type="italics"/>
              Siano quante ſi voglia rote ne gli aſſi A, B, C, che ſi tocchino: ciò
                <lb/>
              è che la A tocchi la B nel ponto D: e la B tocchila C nel ponto E:
                <lb/>
              & intendaſi nella circonferenza di A eſſer la potenza F: e nella cir
                <lb/>
              conferenza di C la potenza G: che l'una rattenga l'altra. </s>
              <s id="N112A6">Dico che
                <lb/>
              le potenze ſono eguali. </s>
              <s id="N112AA">Si moſtra: percio che la poßanza in F, è dell'­
                <lb/>
              iſteſſo momento, che ſe fuſſe in D, dell'iſteſſa rota A: ma il ponto
                <lb/>
              D, è ponto commune a due rote: e la poſſanza in D della rota B,
                <lb/>
              è quanto fuſſe in E: ſarà dunque la poſſanza in F l'iſteſſo che ſi fuſſe
                <lb/>
              in E: perche
                <expan abbr="dũque">dunque</expan>
              la poſſanza in F ſi annulla con la poſſanza in G, ſo
                <lb/>
              no li loro momenti eguali. </s>
              <s id="N112BA">Ma le poſſanze che ſono in un'iſteſſa rota
                <lb/>
              di momenti eguali, ſono eguali: dunque la poſſanza in F è uguale alla
                <lb/>
              poſſanza in G. </s>
              <s id="N112C0">Jl che ſi hauea da moſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N112C4" type="head">
              <s id="N112C6">
                <emph type="italics"/>
              PROPOSITION.
                <emph.end type="italics"/>
                <lb/>
              II. </s>
            </p>
            <p id="N112CE" type="main">
              <s id="N112D0">Delle due rote in vno aſſe la poſſanza, che fa egual
                <lb/>
              momento nella rota magiore è di valor minore: e nel
                <lb/>
              la minore è di valor maggiore, nella ragione de ſemi
                <lb/>
              diametri reciproca. </s>
            </p>
            <p id="N112D8" type="head">
              <s id="N112DA">
                <emph type="italics"/>
              Dimostratione.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N112E0" type="main">
              <s id="N112E2">
                <emph type="italics"/>
              Siano ſu l' aſſe A le rote A B, A C: & intendaſi la poſſanza B,
                <lb/>
              in circonferenza della rota maggiore, hauere egual momento alla
                <lb/>
              poſſanza C in circonferenza della rota minore. </s>
              <s id="N112EA">Dico che la poſſan­
                <lb/>
              za B è minore della poſſanza C, ſecondo la ragione di C A ad A B. </s>
              <lb/>
              <s id="N112EF">Si moſtra: intendaſi nell circonferenza di A C eſſer poſſanza eguale
                <lb/>
              a B, che ſia D: ſarà il momento di B al momento di D, nella ragion
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>