DelMonte, Guidubaldo, Le mechaniche

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      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N106DF">
            <pb pagenum="23" xlink:href="037/01/061.jpg"/>
            <p id="id.2.1.406.0.0" type="main">
              <s id="id.2.1.406.1.0">
                <emph type="italics"/>
              Sia poi la bilancia AB, il cui centro C stia ſotto la bilancia, & ſiano in AB
                <lb/>
              peſi eguali, & ſia moſſa la bilancia in EF. </s>
              <s id="id.2.1.406.2.0">Dico che il peſo ha grauezza maggio­
                <lb/>
              re in F, che in E. </s>
              <s id="N12267">&
                <lb/>
              perciò la bilancia EF
                <lb/>
              eſſere per mouerſi in giù
                <lb/>
              dalla parte di F. </s>
              <s id="id.2.1.406.3.0">ſia allun
                <lb/>
              gata la linea DC dall'una
                <lb/>
              parte, & dall'altra fin
                <lb/>
              nel centro del mondo S,
                <lb/>
              & fin ad O, & ſia tira
                <lb/>
              ta la linea HS, alla qua
                <lb/>
              le dai punti EF ſiano ti
                <lb/>
              rate le linee GEK FL
                <lb/>
              egualmente diſtanti, &
                <lb/>
              ſiano congiunte le CE
                <lb/>
              CF: & dal centro C
                <expan abbr="cõ">con</expan>
                <lb/>
              lo ſpatio CE deſcriuaſi
                <lb/>
              il cerchio AEO B</s>
              <s id="id.2.1.406.4.0">ſi dimoſtrerà ſimilmente
                <lb/>
              i punti AB EF eſſe­
                <lb/>
              re nella circonferenza del
                <lb/>
              cerchio, & che la diſceſa
                <lb/>
              della bilancia EF inſie­
                <lb/>
              me co'peſi ſi fà diritta ſe
                <lb/>
              condo la linea HS: &
                <lb/>
              de i peſi poſti in EF ſe­
                <lb/>
              condo le linee GK FL
                <lb/>
              egualmente diſtanti da
                <lb/>
              HS. </s>
              <s id="id.2.1.406.5.0">Et percioche l'ango
                <lb/>
              lo CFP è eguale all'an
                <lb/>
              golo CEO ſarà l'ango­
                <lb/>
              lo HFP maggiore del­
                <lb/>
              l'angolo HEO. </s>
              <s id="id.2.1.406.6.0">ma l'an
                <emph.end type="italics"/>
                <arrow.to.target n="note123"/>
                <lb/>
                <emph type="italics"/>
              golo HFL è eguale al­
                <lb/>
              l'angolo HEG. </s>
              <s id="id.2.1.406.7.0">Da qua
                <lb/>
              li ſe ſaranno leuati via
                <lb/>
              gli angoli HFP HEO,
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.061.1.jpg" xlink:href="037/01/061/1.jpg" number="44"/>
                <lb/>
                <emph type="italics"/>
              ſarà l'angolo LFP minore dell' angolo GEO. </s>
              <s id="id.2.1.406.8.0">Per laqual coſa la ſceſa del peſo
                <lb/>
              poſto in F ſarà piu diritta della aſceſa del peſo poſto in E. </s>
              <s id="id.2.1.406.9.0">Adunque la poſſanza
                <lb/>
              naturale del peſo poſto in F ſupererà la reſiſtenza della violentia del peſo poſto in
                <lb/>
              E. </s>
              <s id="N122DC">& percio hauerà maggior grauezza il peſo di F, che il peſo di E. </s>
              <s id="id.2.1.406.10.0">Adunque
                <lb/>
              il peſo di F ſi mouerà in giù, & il peſo di E ſi mouerà in sù.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.409.0.0" type="margin">
              <s id="id.2.1.409.1.0">
                <margin.target id="note123"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              29.
                <emph type="italics"/>
              del primo.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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