DelMonte, Guidubaldo, Le mechaniche

Page concordance

< >
Scan Original
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
< >
page |< < of 270 > >|
    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N106DF">
            <pb pagenum="23" xlink:href="037/01/061.jpg"/>
            <p id="id.2.1.406.0.0" type="main">
              <s id="id.2.1.406.1.0">
                <emph type="italics"/>
              Sia poi la bilancia AB, il cui centro C stia ſotto la bilancia, & ſiano in AB
                <lb/>
              peſi eguali, & ſia moſſa la bilancia in EF. </s>
              <s id="id.2.1.406.2.0">Dico che il peſo ha grauezza maggio­
                <lb/>
              re in F, che in E. </s>
              <s id="N12267">&
                <lb/>
              perciò la bilancia EF
                <lb/>
              eſſere per mouerſi in giù
                <lb/>
              dalla parte di F. </s>
              <s id="id.2.1.406.3.0">ſia allun
                <lb/>
              gata la linea DC dall'una
                <lb/>
              parte, & dall'altra fin
                <lb/>
              nel centro del mondo S,
                <lb/>
              & fin ad O, & ſia tira
                <lb/>
              ta la linea HS, alla qua
                <lb/>
              le dai punti EF ſiano ti
                <lb/>
              rate le linee GEK FL
                <lb/>
              egualmente diſtanti, &
                <lb/>
              ſiano congiunte le CE
                <lb/>
              CF: & dal centro C
                <expan abbr="cõ">con</expan>
                <lb/>
              lo ſpatio CE deſcriuaſi
                <lb/>
              il cerchio AEO B</s>
              <s id="id.2.1.406.4.0">ſi dimoſtrerà ſimilmente
                <lb/>
              i punti AB EF eſſe­
                <lb/>
              re nella circonferenza del
                <lb/>
              cerchio, & che la diſceſa
                <lb/>
              della bilancia EF inſie­
                <lb/>
              me co'peſi ſi fà diritta ſe
                <lb/>
              condo la linea HS: &
                <lb/>
              de i peſi poſti in EF ſe­
                <lb/>
              condo le linee GK FL
                <lb/>
              egualmente diſtanti da
                <lb/>
              HS. </s>
              <s id="id.2.1.406.5.0">Et percioche l'ango
                <lb/>
              lo CFP è eguale all'an
                <lb/>
              golo CEO ſarà l'ango­
                <lb/>
              lo HFP maggiore del­
                <lb/>
              l'angolo HEO. </s>
              <s id="id.2.1.406.6.0">ma l'an
                <emph.end type="italics"/>
                <arrow.to.target n="note123"/>
                <lb/>
                <emph type="italics"/>
              golo HFL è eguale al­
                <lb/>
              l'angolo HEG. </s>
              <s id="id.2.1.406.7.0">Da qua
                <lb/>
              li ſe ſaranno leuati via
                <lb/>
              gli angoli HFP HEO,
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.061.1.jpg" xlink:href="037/01/061/1.jpg" number="44"/>
                <lb/>
                <emph type="italics"/>
              ſarà l'angolo LFP minore dell' angolo GEO. </s>
              <s id="id.2.1.406.8.0">Per laqual coſa la ſceſa del peſo
                <lb/>
              poſto in F ſarà piu diritta della aſceſa del peſo poſto in E. </s>
              <s id="id.2.1.406.9.0">Adunque la poſſanza
                <lb/>
              naturale del peſo poſto in F ſupererà la reſiſtenza della violentia del peſo poſto in
                <lb/>
              E. </s>
              <s id="N122DC">& percio hauerà maggior grauezza il peſo di F, che il peſo di E. </s>
              <s id="id.2.1.406.10.0">Adunque
                <lb/>
              il peſo di F ſi mouerà in giù, & il peſo di E ſi mouerà in sù.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.409.0.0" type="margin">
              <s id="id.2.1.409.1.0">
                <margin.target id="note123"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              29.
                <emph type="italics"/>
              del primo.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
Impressum