Archimedes
,
Natation of bodies
,
1662
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[Figure 61]
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[Figure 62]
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[Figure 63]
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[Figure 64]
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[Figure 69]
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[Figure 70]
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[Figure 71]
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[Figure 72]
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[Figure 73]
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[Figure 74]
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[Figure 75]
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(d) By 5 of our ſe
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cond of
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Conicks.</
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(e)
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By 29 of the
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firſt.
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(f)
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By 39 of our
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firſt of
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<
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>Therefore, A Q and A M do make equall Acute Angles with
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the Diameters of the Portions.]
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We demonſtrate this as in the Commentaries
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upon the ſecond Concluſion.
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E</
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<
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>It is to be demonſtrated in the ſame manner, that the Portion
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that hath the ſame proportion in Gravity to the Liquid, that the
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Square P F hath to the Square B D,
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being demitted into the Liquid, ſo,
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as that its Baſe touch not the Li
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quid, it ſhall ſtand inclined, ſo, as
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that its Baſe touch the Surface of the
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Liquid in one point only; and its Axis
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ſhall make therewith an angle equall
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to the Angle
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Let the Portion be to the
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Liquid in Gravity, as the Square P F to the
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Square B D: and being demitted into the
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Liquid, ſo inclined, as that its Baſe touch not
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the Liquid, let it be cut thorow the Axis by a
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Plane erect to the Surface of the Liquid, that
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that the Section may be A M O L, the Section
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of a Rightangled Cone; and, let the Section of the Liquids Surface be I O; and the Axit
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of the Portion and Diameter of the Section B D; which let be cut into the ſame parts as
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we ſaid before, and draw M N parallel to I O, that it may touch the Section in the Point
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M; and M T parallel to B D, and P M S perpe ndicular to the ſame. </
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>It is to be demon
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strated, that the Portion ſhall not reſt, but ſhall incline, ſo, as that it touch the Liquids
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Surface, in one Point of its Baſe only. </
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<
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>For,
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draw P C perpendicular to B D; and drawing
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a Line from A to F, prolong it till it meet with
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the Section in
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and thorow P draw P
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pa
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rallel to A Q: Now, by the things allready de
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monſtrated by us, A F and F Q ſhall be equall
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to one another. </
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>And being that the Portion hath
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the ſame proportion in Gravity unto the Liquid,
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that the Square P F hath to the Square B D; and
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ſeeing that the part ſubmerged, hath the ſame pro-
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partion to the whole Portion; that is, the Squàre
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M T to the Square B D; (g) the Square M T
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ſhall be equall to the Square P F; and, by the
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ſame reaſon, the Line M T equall to the Line
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P F. </
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<
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>So that there being drawn in the equall & like
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portions A P Q Land A M O L, the Lines A Q and I O which cut off equall Portions, the
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firſt from the Extreme term of the Baſe, the laſt not from the Extremity; it followeth, that
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A Q drawn from the Extremity, containeth a leſſer Acute Angle with the Diameter of the
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Portion, than I O: But the Line P
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is parallel to the Line A Q, and M N to I O: There
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fore, the Angle at
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ſhall be leſſer than the Angle at N; but the Line B C greater than B S;
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and S R, that is, M X, greater than C R, that is, than P Y: and, by the ſame reaſon, X T
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leſſer than Y F. And, ſince P Y is double to Y F, M X ſhall be greater than double to
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Y F, and much greater than double of X T. </
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>Let M H be double to H T, and draw a
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Line from H to K, prolonging it. </
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<
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>Now, the Centre of Gravity of the whole Portion
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ſhall be the Point K; of the part within the Liquid H; and of the Remaining part above
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the Liquid in the Line H K produced, as ſuppoſe in
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It ſhall be demonſtrated in the ſame
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manner, as before, that both the Line K H and thoſe that are drawn thorow the Points H
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and
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parallel to the ſaid K H, are perpendicular to the Surface of the Liquid: The
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Portion therefore, ſhall not reſt; but when it ſhall be enclined ſo far as to touch the Sur
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face of the Liquid in one Point and no more, then it ſhall ſtay. </
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<
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>For the Angle at N
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