Archimedes
,
Natation of bodies
,
1662
Text
Text Image
XML
Document information
None
Concordance
Figures
Thumbnails
Table of figures
<
1 - 30
31 - 60
61 - 75
>
[Figure 61]
Page: 61
[Figure 62]
Page: 61
[Figure 63]
Page: 62
[Figure 64]
Page: 62
[Figure 65]
Page: 63
[Figure 66]
Page: 63
[Figure 67]
Page: 64
[Figure 68]
Page: 65
[Figure 69]
Page: 65
[Figure 70]
Page: 65
[Figure 71]
Page: 66
[Figure 72]
Page: 67
[Figure 73]
Page: 67
[Figure 74]
Page: 67
[Figure 75]
Page: 68
<
1 - 30
31 - 60
61 - 75
>
page
|<
<
of 68
>
>|
<
archimedes
>
<
text
>
<
body
>
<
chap
>
<
p
type
="
main
">
<
s
>
<
pb
xlink:href
="
073/01/065.jpg
"
pagenum
="
399
"/>
but one Point only. </
s
>
<
s
>For let it be de
<
lb
/>
<
figure
id
="
id.073.01.065.1.jpg
"
xlink:href
="
073/01/065/1.jpg
"
number
="
68
"/>
<
lb
/>
mitted into the Liquid, as hath been
<
lb
/>
ſaid; and let it firſt be ſo inclined, as
<
lb
/>
that its Baſe do not in the leaſt
<
lb
/>
touch the Surface of the Liquid. </
s
>
<
s
>And
<
lb
/>
then it being cut thorow the Axis,
<
lb
/>
by a Plane erect unto the Surface of
<
lb
/>
the Liquid, let the Section of the
<
lb
/>
Portion be A N Z G; that of the
<
lb
/>
Liquids Surface E Z; the Axis of
<
lb
/>
the Portion and Diameter of the
<
lb
/>
Section B D; and let B D be cut in
<
lb
/>
the Points K and R, as before; and
<
lb
/>
draw N L parallel to E Z, and touching the Section A N Z G
<
lb
/>
in N, and N S perpendicular to
<
lb
/>
<
figure
id
="
id.073.01.065.2.jpg
"
xlink:href
="
073/01/065/2.jpg
"
number
="
69
"/>
<
lb
/>
B D. Now, ſeeing that the Por
<
lb
/>
tion is in Gravity unto the Liquid,
<
lb
/>
as the Square made of the Line
<
lb
/>
is to the Square B D;
<
foreign
lang
="
grc
">ψ</
foreign
>
ſhall
<
lb
/>
be equall to N T: Which is to
<
lb
/>
be demonſtrated as above: And,
<
lb
/>
therefore, N T is alſo equall to
<
lb
/>
V I: The Portions, therefore,
<
lb
/>
A V Q and E N Z are equall to
<
lb
/>
one another. </
s
>
<
s
>And, ſince that in
<
lb
/>
the Equall and like Portions A V
<
lb
/>
Q L and A N Z G, there are drawn A Q and E Z, cutting off
<
lb
/>
equall Portions, that from the
<
lb
/>
<
figure
id
="
id.073.01.065.3.jpg
"
xlink:href
="
073/01/065/3.jpg
"
number
="
70
"/>
<
lb
/>
Extremity of the Baſe, this not
<
lb
/>
from the Extreme, that which is
<
lb
/>
drawn from the Extremity of the
<
lb
/>
Baſe, ſhall make the Acute Angle
<
lb
/>
with the Diameter of the Portion
<
lb
/>
leſſer: and in the Triangles N L S
<
lb
/>
and V
<
foreign
lang
="
grc
">ω</
foreign
>
C, the Angle at L is
<
lb
/>
greater than the Angle at
<
foreign
lang
="
grc
">ω</
foreign
>
:
<
lb
/>
Therefore, B S ſhall be leſſer
<
lb
/>
than B C; and S R leſſer than
<
lb
/>
C R: and, conſequently, N X
<
lb
/>
greater than V H; and X T leſſer than H I. Seeing, therefore,
<
lb
/>
that V Y is double to Y I; It is manifeſt, that N X is greater than
<
lb
/>
double to X T. </
s
>
<
s
>Let N M be double to M T: It is manifeſt, from what
<
lb
/>
hath been ſaid, that the Portion ſhall not reſt, but will incline, untill
<
lb
/>
that its Bafe do touch the Surface of the Liquid: and it toucheth it in
<
lb
/>
one Point only, as appeareth in the Figure: And other things </
s
>
</
p
>
</
chap
>
</
body
>
</
text
>
</
archimedes
>