DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N106DF">
            <pb pagenum="28" xlink:href="037/01/071.jpg"/>
            <figure id="id.037.01.071.1.jpg" xlink:href="037/01/071/1.jpg" number="58"/>
            <figure id="id.037.01.071.2.jpg" xlink:href="037/01/071/2.jpg" number="59"/>
            <figure id="id.037.01.071.3.jpg" xlink:href="037/01/071/3.jpg" number="60"/>
            <p id="id.2.1.459.0.0" type="main">
              <s id="id.2.1.459.1.0">
                <emph type="italics"/>
              Et ſe l'angolo ACB foſſe ſoprala linea AB, & il centro della bilancia H; &
                <lb/>
              & la linea CH ſoſteneſſe la bilancia; & ſi moueſſe la bilancia in EKF; la bilan
                <lb/>
              cia EKF ritornerà in ACB.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.460.0.0" type="main">
              <s id="id.2.1.460.1.0">
                <emph type="italics"/>
              Ma ſe il centro della bilancia ſarà D, mouaſi in qualunque modo la bilancia, doue ſi
                <lb/>
              laſcierà, lui rimarrà.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.461.0.0" type="main">
              <s id="id.2.1.461.1.0">
                <emph type="italics"/>
              Se poi il punto H ſarà ſotto la linea AB; allhora la bilancia EKF ſi mouerà in
                <lb/>
              giu dalla parte di F.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.462.0.0" type="main">
              <s id="id.2.1.462.1.0">
                <emph type="italics"/>
              Et con ſimile ragione in tutto, ſe l'ango­
                <lb/>
              lo ACB ſarà ſotto la linea AB;
                <lb/>
              & ſia il centro della bilancia H, &
                <lb/>
              ſia la bilancia ſoſtentata dalla linea
                <lb/>
              CH; ſe la bilancia moueraßi da queſto
                <lb/>
              ſito, ſi mouerà in giu dalla parte del pe
                <lb/>
              ſo più baſſo. </s>
              <s id="id.2.1.462.2.0">& ſe il centro della bilan­
                <lb/>
              cia ſia D; rimarrà doue ſi laſcierà. </s>
              <s id="id.2.1.462.3.0">che
                <lb/>
              ſe ſarà in K; & da cotale ſito ſi mo
                <lb/>
              uerà, ritornerà ad ogni modo nello iſteſ
                <lb/>
              ſo. </s>
              <s id="id.2.1.462.4.0">Le quali coſe tutte da quel che in
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.071.4.jpg" xlink:href="037/01/071/4.jpg" number="61"/>
                <lb/>
                <emph type="italics"/>
              principio dicemmo ſono manifeste. </s>
              <s id="id.2.1.462.5.0">ſimilmente ſe il centro della bilancia ſarà poſto
                <lb/>
              in vno della bracia della bilancia, ò dentro, ò fuori, ò in qual ſi voglia modo trouere
                <lb/>
              mo le coſe iſteſſe.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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