DelMonte, Guidubaldo, Le mechaniche

Table of figures

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page |< < of 270 > >|
    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N106DF">
            <p id="id.2.1.224.0.0" type="main">
              <s id="id.2.1.224.12.0">
                <pb pagenum="30" xlink:href="037/01/075.jpg"/>
                <emph type="italics"/>
              ad O, & il peſo F eguale parimente al Q, & la parte di R eguale ad N; ſa
                <lb/>
              ranno i peſi LM eguali a i peſi E\1</s>
              <s id="id.2.1.224.13.0">& percioche ſi come AC verſo CG, co
                <emph.end type="italics"/>
                <arrow.to.target n="note66"/>
                <lb/>
                <emph type="italics"/>
              ſi è il peſo E al peſo L, i peſi EL peſeranno egualmente. </s>
              <s id="id.2.1.224.14.0">ſimilmente percioche
                <lb/>
              ſi come AC è verſo CB, coſi il peſo F è al peſo M, i peſi FM peſeranno
                <lb/>
              anco egualmente. </s>
              <s id="id.2.1.224.15.0">i peſi dunque LM peſeranno egualmente co'peſi EF attacca­
                <lb/>
              ti in BG. </s>
              <s id="id.2.1.224.16.0">& eſſendo la diſtanza CA eguale alla diſtanza CH, ſe dunque am
                <lb/>
              bidue i peſi EF ſaranno attaccati in H, i peſi LM peſeranno egualmente co'
                <emph.end type="italics"/>
                <arrow.to.target n="note67"/>
                <lb/>
                <emph type="italics"/>
              peſi EF attaccati in H. </s>
              <s id="id.2.1.224.17.0">Ma LM peſa ancora egualmente con EF in GB.
                <lb/>
              </s>
              <s id="id.2.1.224.18.0">Adunque ſaranno egualmente graui i peſi EF in GB attaccati come in H. </s>
              <s id="id.2.1.224.19.0">pe
                <emph.end type="italics"/>
                <arrow.to.target n="note68"/>
                <lb/>
                <emph type="italics"/>
              ſeranno dunque tanto in BG quanto attaccati in H.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.225.0.0" type="margin">
              <s id="id.2.1.225.1.0">
                <margin.target id="note58"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              17.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.226.0.0" type="margin">
              <s id="id.2.1.226.1.0">
                <margin.target id="note59"/>
                <emph type="italics"/>
              Per la
                <expan abbr="con­ſeguẽza">con­ſeguenza</expan>
              della
                <emph.end type="italics"/>
              4.
                <emph type="italics"/>
              del
                <emph.end type="italics"/>
              5. </s>
            </p>
            <p id="id.2.1.227.0.0" type="margin">
              <s id="id.2.1.227.1.0">
                <margin.target id="note60"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              17.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.228.0.0" type="margin">
              <s id="id.2.1.228.1.0">
                <margin.target id="note61"/>
                <emph type="italics"/>
              Per la
                <expan abbr="conſeguẽza">conſeguenza</expan>
              della
                <emph.end type="italics"/>
              4.
                <emph type="italics"/>
              del
                <emph.end type="italics"/>
              5. </s>
            </p>
            <p id="id.2.1.229.0.0" type="margin">
              <s id="id.2.1.229.1.0">
                <margin.target id="note62"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              18.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.230.0.0" type="margin">
              <s id="id.2.1.230.1.0">
                <margin.target id="note63"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              16.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.231.0.0" type="margin">
              <s id="id.2.1.231.1.0">
                <margin.target id="note64"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              11.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.232.0.0" type="margin">
              <s id="id.2.1.232.1.0">
                <margin.target id="note65"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              16.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.233.0.0" type="margin">
              <s id="id.2.1.233.1.0">
                <margin.target id="note66"/>
                <emph type="italics"/>
              Perla
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              del primo di Archimede delle coſe che peſano egualmente.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.234.0.0" type="margin">
              <s id="id.2.1.234.1.0">
                <margin.target id="note67"/>
                <emph type="italics"/>
              Per lo
                <emph.end type="italics"/>
              2.
                <emph type="italics"/>
                <expan abbr="cõ.">con.</expan>
              della not di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.235.0.0" type="margin">
              <s id="id.2.1.235.1.0">
                <margin.target id="note68"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              3.
                <emph type="italics"/>
                <expan abbr="cõ.">con.</expan>
              della not ai questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.037.01.075.1.jpg" xlink:href="037/01/075/1.jpg" number="63"/>
            <p id="id.2.1.237.0.0" type="main">
              <s id="id.2.1.237.1.0">
                <emph type="italics"/>
              Ma ſiano i peſi EF attaccati in CB; & ſia C il centro della bilancia, & diuidaſi
                <lb/>
              CB in H, per modo che CH verſo HB ſia come il peſo F al peſo E. </s>
              <s id="id.2.1.237.2.0">Dico
                <lb/>
              che i peſi EF peſeranno tanto in CB quanto nel punto H. </s>
              <s id="id.2.1.237.3.0">facciaſi CA egua
                <lb/>
              le à CH, & come CA verſo CB; coſi facciaſi il peſo F verſo vn'altro, che
                <lb/>
              ſia D, ilquale ſi appicchi in A. </s>
              <s id="id.2.1.237.4.0">Hor percioche CH è eguale à CA, ſarà CH
                <lb/>
              verſo CB, come F à D; & ben è maggiore CB di CH, però il peſo D ſa
                <lb/>
              rà maggiore del peſo F. </s>
              <s id="id.2.1.237.5.0">Diuidaſi dunque il D in due parti GK, & ſia il G
                <emph.end type="italics"/>
                <arrow.to.target n="note69"/>
                <lb/>
                <emph type="italics"/>
              eguale allo F; ſarà BC à CH come GK verſo il G; et diuidendo, come BH
                <lb/>
              ad HC, coſi K verſo G; & conuertendo come CH ad HB, coſi G ver­
                <emph.end type="italics"/>
                <arrow.to.target n="note70"/>
                <lb/>
                <emph type="italics"/>
              ſo K. </s>
              <s id="id.2.1.237.6.0">& come CH ad HB, coſi è F verſo E. </s>
              <s id="id.2.1.237.7.0">Dunque come G ver­
                <lb/>
              ſo K coſi è F ad E. </s>
              <s id="N12C52">& permutando come G ad F, coſi K ad E. </s>
              <s id="N12C54">& per­
                <emph.end type="italics"/>
                <arrow.to.target n="note71"/>
                <lb/>
                <emph type="italics"/>
              che GF ſono eguali, ſaranno anche KE tra loro eguali. </s>
              <s id="id.2.1.237.8.0">Concioſia dunque che
                <lb/>
              la parte G ſia eguale ad F, & il K ad eſſo E; ſarà tutto il GK eguale a i pe
                <emph.end type="italics"/>
                <arrow.to.target n="note72"/>
                <lb/>
                <emph type="italics"/>
              ſi EF. </s>
              <s id="N12C6D">& percioche AC è eguale à CH; ſe dunque i peſi EF ſaranno penden
                <lb/>
              ti dal punto H, il peſo D peſerà egualmente co'peſi EF attaccati in H. </s>
              <s id="id.2.1.237.9.0">Ma
                <lb/>
              peſa anche egualmente con eßi in CB, cioè F in B, & E in C; per eſſere
                <lb/>
              come AC verſo CB, coſi F verſo D: percioche il peſo E pendente da C
                <lb/>
              centro della bilancia non è cauſa, che la bilancia ſi moua in alcuna delle due parti.
                <lb/>
              </s>
              <s id="id.2.1.237.10.0">tanto ſaranno dunque graui i peſi EF in CB, quanto in H appicati.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.239.0.0" type="margin">
              <s id="id.2.1.239.1.0">
                <margin.target id="note69"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              17.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.240.0.0" type="margin">
              <s id="id.2.1.240.1.0">
                <margin.target id="note70"/>
                <emph type="italics"/>
              Per la
                <expan abbr="conſeguẽza">conſeguenza</expan>
              della
                <emph.end type="italics"/>
              4.
                <emph type="italics"/>
              del
                <emph.end type="italics"/>
              5. </s>
            </p>
            <p id="id.2.1.241.0.0" type="margin">
              <s id="id.2.1.241.1.0">
                <margin.target id="note71"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              11.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.242.0.0" type="margin">
              <s id="id.2.1.242.1.0">
                <margin.target id="note72"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              16.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>