Clavius, Christoph, Geometria practica

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8050GEOMETR. PRACT. LIB. I.
Nam in triangulo rectangulo A B D, cui{us} angul{us}
D
, rect{us}, ſiex B, per D, ſemicircul{us} deſcribatur E F D,
erit
A E, differentia inter baſem A B, &
lat{us} B D: At A F, ſumma erit baſis A B,
&
eiuſdem lateris B D, cum B D, B E, B F, rectæ ſint æqual{es}. Dico igitur rectang ulum
ſub
A E, A F, æquale eſſe quadrato lateris A D.
Recta enim A D, cum perpendicu-
laris
ſit ad ſemidiam{et}rum B D, ſemicirculum tang{et} in D.
lgitur 22Coroll. 16.
ter
.
gulum ſub A E, A F, quadrato tangentis A D, æquale erit,
quod
erat demonſtrandum.
3336. ter.
16[Figure 16]

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