DelMonte, Guidubaldo, Le mechaniche

Table of figures

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N106DF">
            <p id="id.2.1.269.0.0" type="main">
              <s id="id.2.1.269.13.0">
                <pb xlink:href="037/01/080.jpg"/>
                <emph type="italics"/>
              coſa per la ſeſta dell'iſteſſo primo di Archimede, i due peſi FG pendenti dal punto C
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note91"/>
                <emph type="italics"/>
              peſeranno tanto, quanto il peſo L pendente dal B; cioè quanto i peſi EF pen­
                <lb/>
              denti da i punti DC. </s>
              <s id="id.2.1.269.14.0">Così percioche i peſi FG tanto peſano quanto i peſi EF,
                <lb/>
              leuato via il peſo comune F, tanto peſerà il peſo G appicato in C, quanto il pe
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.080.1.jpg" xlink:href="037/01/080/1.jpg" number="70"/>
                <lb/>
                <emph type="italics"/>
              ſo E in D. </s>
              <s id="id.2.1.269.15.0">Et perciò il peſo F al peſo E hà quella proportione in grauezza,
                <lb/>
              che hà al peſo G. </s>
              <s id="id.2.1.269.16.0">Ma il peſo F verſo il G era come CA verſo AD. </s>
              <s id="N1301A">adun
                <lb/>
              que il peſo F ancora verſo il peſo E hauerà quella proportione in grauezza, che
                <lb/>
              ha CA verſo AD che biſognaua moſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.271.0.0" type="margin">
              <s id="id.2.1.271.1.0">
                <margin.target id="note87"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              5.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.272.0.0" type="margin">
              <s id="id.2.1.272.1.0">
                <margin.target id="note88"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              18.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.273.0.0" type="margin">
              <s id="id.2.1.273.1.0">
                <margin.target id="note89"/>
                <emph type="italics"/>
              Per la conſeguenza della quarta del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.274.0.0" type="margin">
              <s id="id.2.1.274.1.0">
                <margin.target id="note90"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              22.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.275.0.0" type="margin">
              <s id="id.2.1.275.1.0">
                <margin.target id="note91"/>
                <emph type="italics"/>
              Per la ſettima del
                <emph.end type="italics"/>
              5. </s>
            </p>
            <p id="id.2.1.276.0.0" type="main">
              <s id="id.2.1.276.1.0">
                <emph type="italics"/>
              Ma ſe nella bilancia BAC ſi faranno pendenti da i punti BC, i peſi EF eguali;
                <lb/>
              Dico ſimilmente, che il peſo E verſo il peſo F hà quella proportione in grauezza,
                <lb/>
              che ha la diſtanza
                <lb/>
              CA alla diſtanza
                <lb/>
              AB. </s>
              <s id="id.2.1.276.2.0">facciaſi AD
                <lb/>
              eguale ad AB, &
                <lb/>
              dal punto D ſia
                <lb/>
              fatto
                <expan abbr="pẽdente">pendente</expan>
              il pe
                <lb/>
              ſo G eguale al pe
                <lb/>
              ſo F, ilquale
                <expan abbr="etiã­">etian­</expan>
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.080.2.jpg" xlink:href="037/01/080/2.jpg" number="71"/>
                <lb/>
                <emph type="italics"/>
              dio ſarà eguale ad E. </s>
              <s id="id.2.1.276.3.0">Et percioche AD è eguale ad AB; i peſi FG peſeran
                <lb/>
              no egualmente, & hauranno la medeſima grauezza. </s>
              <s id="id.2.1.276.4.0">Et concioſia, che la grauezza
                <lb/>
              del peſo E verſo la grauezza del peſo G ſia come CA ad AD; ſarà la gra­
                <lb/>
              uezza del peſo E verſo la grauezza del peſo F, come CA ad AD, cioè CA
                <lb/>
              ad AB, che parimente era da moſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.278.0.0" type="head">
              <s id="id.2.1.278.1.0">Altramente. </s>
            </p>
            <p id="id.2.1.279.0.0" type="main">
              <s id="id.2.1.279.1.0">
                <emph type="italics"/>
              Sia la bilancia BAC, col ſuo centro A: & ne i punti BC ſiano appiccati peſi
                <lb/>
              eguali GF, & ſia prima il centro A, come ſi vuole, fra B, & C. </s>
              <s id="id.2.1.279.2.0">Dico, che
                <lb/>
              il peſo F verſo il peſo G hà quella proportione in grauezza, che ha la diſtanza
                <lb/>
              CA alla diſtanza AB. </s>
              <s id="id.2.1.279.3.0">Facciaſi come BA verſo AC, coſi il peſo F ad vn­
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>