Salusbury, Thomas
,
Mathematical collections and translations (Tome I)
,
1667
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<
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>PROP. XIII. PROBL. IV.</
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There being given the greateſt Weight that can be ſup
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ported at the middle of a Cylinder or Priſme, where
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the Reſiſtance is leafl; and there being given a
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Weight greater than that, to find in the ſaid Cylin
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der, the point at which the given greater Weight may
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be ſupporited as the greateſt Weight.
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>Let the given weight greater than the greateſt weight that
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can be ſupported at the middle of the Cylinder A B, have
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unto the ſaid greateſt weight, the proportion of the line E
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to F: it is required to find the point in the Cylinder at which the
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ſaid given weight commeth to be ſupported as the biggeſt. </
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<
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>Be
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tween E and F let G be a Mean-Proportional; and as E is to G,
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ſo let A D be to S, S ſhall be leſſer than A D. </
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<
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>Let A D be the
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Diameter of the Semicircle A H D: in which ſuppoſe A H equal
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to S; and joyn together H and D, and take D R equal to it.
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<
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>I ſay that R is the point ſought, at which the given weight,
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greater than the greateſt that can be ſupported at the middle of the
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Cylinder D, would become as the greateſt weight. </
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<
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>On the length
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B
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A deſcribe the Semicircle A N B, and raiſe the Perpendicular
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RN, and conjoyn N and
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D: And becauſe the two
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Squares N R and R D are
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equal to the Square N D;
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that is, to the Square A D;
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that is, to the two A H and
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and H D; and H D is equal
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to the Square D R: There
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fore the Square N R, that
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is, the Rectangle A R B
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ſhall be equal to the Square A H; that is, to the Square S: But
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the Square S is to the Square A D, as F to E; that is, as the
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greateſt ſupportable Weight at D to the given greater Weight:
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Therefore this greater ſhall be ſupported at R, as the greateſt
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that can be there ſuſtained. </
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<
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>Which is that that we ſought.</
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<
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>SAGR. </
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>I underſtand you very well, and am conſidering that
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the Priſme A B having alwayes more ſtrength and reſiſtance a
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gainſt Preſſion in the parts that more and more recede from the
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middle, whether in very great and heavy Beams one may take </
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