Salusbury, Thomas
,
Mathematical collections and translations (Tome I)
,
1667
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<
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>THEOR. IX. PROP. IX.</
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<
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>If two Planes be inclined at pleaſure from a point
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in a Line parallel to the Horizon, and be inter
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ſected by a Line which may make Angles Al
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ternately equal to the Angles contained be
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tween the ſaid Planes and Horizontal Parallel,
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the Motion along the parts cut off by the ſaid
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Line, ſhall be performed in equal Times.</
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From off the point C of the Horizontal Line X, let any two Planes
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be inclined at pleaſure C D and C E, and in any point of the
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Line C D make the Angle C D F equal to the Angle X C E:
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and let the Line D F cut the Plane C E in F, in ſuch a manner that
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the Angles C D F and C F D may be equal to the Angles X C E, L C D
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Alternately taken. </
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>I ſay, that
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the Times of the Deſcents along
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C D and C F are equal. </
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that (the Angle C D F being
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ſuppoſed equal to the Angle
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X C E) the Angle C F D is
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equal to the Angle D C L, is
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manifeſt. </
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>For the Common An
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gle D C F being taken from the
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three Angles of the Triangle
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C D F equal to two Right An
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gles, to which are equal all the Angles made with to the Line L X
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at the point C, there remains in the Triangle two Angles C D F and
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C F D, equal to the two Angles X C E and L C D: But it was ſup
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poſed that C D F is equal to the Angle X C E: Therefore the remaining
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Angle C F D is equal to the remaining angle D C L. </
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<
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>Let the Plane
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C E be ſuppoſed equal to the Plane C D, and from the points D and
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E raiſe the Perpendiculars D A and E B, unto the Horizontal Paral
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lel X L; and from C unto D F let fall the Perpendicular C G. </
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<
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>And
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becauſe the Angle C D G is equal to the Angle E C B; and becauſe
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D G C and C B E are Right Angles; The Triangles C D G and
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C B E ſhall be equiangled: And as D C is to C G, ſo let C E be
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to E B: But D C is equal to C E: Therefore C G ſhall be equal to
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E B. </
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>And inregard that of the Triangles D A C and C G F, the An
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gles C and A are equal to the Angles F and G: Therefore as C D is to
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D A, ſo ſhall F C be to C G; and Alternately, as D C is to C F, ſo
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