DelMonte, Guidubaldo, Le mechaniche

Table of figures

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      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N13354">
            <p id="id.2.1.321.0.0" type="main">
              <s id="id.2.1.321.2.0">
                <pb xlink:href="037/01/086.jpg"/>
                <arrow.to.target n="note99"/>
                <emph type="italics"/>
              verſo la CB. </s>
              <s id="id.2.1.321.3.0">Facciaſi come la BC alla CA, coſi il peſo D ad vn'altro peſo
                <lb/>
              E, talche ſe egli in B ſarà appiccato, peſerà
                <expan abbr="egualmẽte">egualmente</expan>
              con D, per eſſer il C cen
                <lb/>
              tro della grauezza di ambidue. </s>
              <s id="id.2.1.321.4.0">Per laqual coſa vna poſſanza eguale ad eſſo E po
                <lb/>
              ſta nel
                <lb/>
              medeſi
                <lb/>
              mo lo
                <lb/>
              go pe­
                <lb/>
              ſerà e­
                <lb/>
              gual­
                <lb/>
              mente
                <lb/>
              con eſ­
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.086.1.jpg" xlink:href="037/01/086/1.jpg" number="79"/>
                <lb/>
                <emph type="italics"/>
              ſo D, nella leua AB, collocando il ſoſtegno ſuo in C, cioè impedirà, che il pe­
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note100"/>
                <emph type="italics"/>
              ſo D non inchini in giuſo, ſi come impediſce il peſo E. </s>
              <s id="id.2.1.321.5.0">Ma la poſſanza di B al
                <lb/>
              peſo D hàla medeſima proportione, che il peſo E ha all'isteſſo D: adunque la
                <lb/>
              poſſanza di B verſo il peſo D ſarà come CA verſo CB; cioè la diſtanza del­
                <lb/>
              la leua dal ſostegno al ſoſtenimento del peſo, alla diſtanza dal ſostegno alla poſſan­
                <lb/>
              za, che biſognaua moſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.324.0.0" type="margin">
              <s id="id.2.1.324.1.0">
                <margin.target id="note99"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              del
                <emph.end type="italics"/>
              1.
                <emph type="italics"/>
              di Archimede delle coſa che
                <expan abbr="egualmẽte">egualmente</expan>
              peſano.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.325.0.0" type="margin">
              <s id="id.2.1.325.1.0">
                <margin.target id="note100"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              7.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.326.0.0" type="main">
              <s id="id.2.1.326.1.0">Di quì ageuolmente ſi puote moſtrare, che
                <expan abbr="quãto">quanto</expan>
              il ſoſtegno ſarà piu
                <lb/>
              vicino al peſo, tanto minor poſſanza ſi ricerca à ſoſtenere il detto
                <lb/>
              peſo. </s>
            </p>
            <p id="id.2.1.327.0.0" type="main">
              <s id="id.2.1.327.1.0">
                <emph type="italics"/>
              Poste le coſe medeſime ſia il ſoſtegno in F piu da preſſo ad A, che C; & facciaſi
                <lb/>
              come BF ad FA, coſi il peſo D ad vn'altro peſo G, ilquale ſe in B ſia ap­
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note101"/>
                <emph type="italics"/>
              piccato; i peſi DG dal ſoſtegno F peſeranno egualmente. </s>
              <s id="id.2.1.327.2.0">Hor percioche BF
                <lb/>
              è mag­
                <lb/>
              giore di
                <lb/>
              BC, &
                <lb/>
              CA
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note102"/>
                <emph type="italics"/>
              maggio
                <lb/>
              re di AF;
                <lb/>
              la
                <lb/>
              propor­
                <lb/>
              tione di
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.086.2.jpg" xlink:href="037/01/086/2.jpg" number="80"/>
                <lb/>
                <emph type="italics"/>
              BF verſo FA ſarà maggiore, che di BC verſo CA: & perciò maggiore anco
                <lb/>
              ſarà la proportione del peſo D al peſo G, che de l'isteſſo D ad E: Dunque il
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note103"/>
                <emph type="italics"/>
              peſo G ſarà minore del peſo E. </s>
              <s id="id.2.1.327.3.0">& concioſia che la poſſanza poſta in B eguale à
                <lb/>
              G peſi egualmente con D, auerrà, che minore poſſanza di quella, laquale è eguale
                <lb/>
              al peſo E ſoſtenterà il peſo D; eſſendo la leua AB, & il ſoſtegno ſuo doue è F,
                <lb/>
              che ſe egli foſſe doue è C. </s>
              <s id="id.2.1.327.4.0">Similmente anche moſtreraſſi, che quanto piu dapreſſo ſa
                <lb/>
              rà il ſoſtegno al peſo D, ſempre vi ſi ricercherà anco poſſanza minore per ſoſtentare
                <lb/>
              il detto peſo D.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.330.0.0" type="margin">
              <s id="id.2.1.330.1.0">
                <margin.target id="note101"/>
                <emph type="italics"/>
              Per la medeſima ſesta.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.331.0.0" type="margin">
              <s id="id.2.1.331.1.0">
                <margin.target id="note102"/>
                <emph type="italics"/>
              Per lo Lemma.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.332.0.0" type="margin">
              <s id="id.2.1.332.1.0">
                <margin.target id="note103"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              10.
                <emph type="italics"/>
              del quinto
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>