DelMonte, Guidubaldo, In duos Archimedis aequeponderantium libros Paraphrasis : scholijs illustrata

Page concordance

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    <archimedes>
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        <body>
          <chap id="N10019">
            <pb xlink:href="077/01/088.jpg" pagenum="84"/>
            <p id="N12F72" type="head">
              <s id="N12F74">PROPOSITIO. X.</s>
            </p>
            <p id="N12F76" type="main">
              <s id="N12F78">Omnis parallelogrammi centrum grauitatis
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              eſt punctum, in quo diametri coincidunt. </s>
            </p>
            <p id="N12F7C" type="main">
              <s id="N12F7E">
                <emph type="italics"/>
              Sit parallelogrammum
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              ABCD. & in ipſo ſit li­
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              nea EF
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              bifariam
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                <expan abbr="ſecãs">ſecans</expan>
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="fig35"/>
                <lb/>
                <emph type="italics"/>
              latera AB CD. itidem­
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              què ſit KL
                <expan abbr="ſecãs">ſecans</expan>
              AC BD
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                <lb/>
              bifariam. </s>
              <s id="N12FA3">conueniant­
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              què EF kL in H.
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              est
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              vti〈que〉 parallelogrammi
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                <lb/>
                <arrow.to.target n="marg85"/>
                <emph type="italics"/>
              ABCD centrum grauita
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              tis in linea EF. hoc enim
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              oſtenſum eſt. </s>
              <s id="N12FBB">eadem verò de cauſa
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              centrum grauitatis ipſius AD
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              est
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              etiam in linea
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              K
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              L. quare punctum H
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              parallelogrammi AD
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              cen­
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              trum grauitatis existit. </s>
              <s id="N12FD3">Verùm in puncio H diametri parallelogram­
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              mi concurrunt.
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              ductis enim lineis AH HB CH HD; quoniam
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              lineæ AE EB EF FD inter ſe ſunt ęquales. </s>
              <s id="N12FDC">ſimiliter quo〈que〉
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              AK KC BL LD inter ſe ęquales; erit EH ipſi HF ęqua
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              lis, cùm ſint ipſis BL LD ęquales. </s>
              <s id="N12FE2">duæ igitur AE EH dua
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                <arrow.to.target n="marg86"/>
              bus DF FH ſunt æquales, & angulus AEH angulo DFH
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                <arrow.to.target n="marg87"/>
              ęqualis; erit triangulum AEH triangulo DFH ęquale. </s>
              <s id="N12FF0">ac
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              propterea angulus EHA angulo FHD æqualis. </s>
              <s id="N12FF4">cùm igitur
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              ſit EHF recta linea, eruntangnli EHA FHD adverticem,
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              & obid AHD recta exiſtit linea. </s>
              <s id="N12FFA">ac per conſe〈que〉ns diame­
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              ter parallelogrammi AD. pariquè ratione oſtendetur BHC
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              rectam eſſe lineam. </s>
              <s id="N13000">ex quibus patet in puncto H
                <expan abbr="vtrã〈que〉">vtran〈que〉</expan>
              dia
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              metrum conuenire. </s>
              <s id="N13008">centrum igitur grauitatis parallelogram­
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              mi AD eſt
                <expan abbr="pũctum">punctum</expan>
              , in quo diametri concurrunt.
                <emph type="italics"/>
              Quare demon
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              stratumeſt, quod propoſitum fuit.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>