DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N13354">
            <p id="id.2.1.375.0.0" type="main">
              <s id="id.2.1.375.4.0">
                <pb pagenum="38" xlink:href="037/01/091.jpg"/>
                <emph type="italics"/>
              FC ſono eguali, ſimilmente i peſi FC peſeranno egualmente, ma i peſi FGC ap­
                <lb/>
              piccati nella leua EBA, il cui ſoſtegno è in B non peſeranno egualmente; ma in­
                <lb/>
              chineranno in giuſo dalla parte di A. </s>
              <s id="id.2.1.469.2.0">Pongaſi dunque in D tanta forza, che i
                <lb/>
              peſi FGC peſino egualmente; ſarà la poſſanza in D eguale al peſo G; peroche
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.091.1.jpg" xlink:href="037/01/091/1.jpg" number="85"/>
                <lb/>
                <emph type="italics"/>
              i peſi FG peſano egualmente, & la poſſanza in D niente altro deue fare, che
                <lb/>
              ſoſtenere il peſo G che non diſcenda. </s>
              <s id="id.2.1.469.3.0">& percioche i peſi FGC, & la poſſanza
                <lb/>
              in D peſano egualmente, leuati via dunque i peſi FG, i quali peſano egualmente,
                <lb/>
              i reſtanti peſeranno egualmente, cioè la poſſanza in D co'l peſo C, cioè la poſſan
                <lb/>
              za in D ſoſterrà il peſo C, talche la leua AB stia come prima. </s>
              <s id="id.2.1.469.4.0">& per eſſere la
                <lb/>
              poſſanza in D eguale al peſo G, & il peſo C eguale al peſo, hauerà la poſſan
                <lb/>
              za posta in D la proportione medeſima al peſo C, che EB, cioè AB à BD. </s>
              <s id="N13851">
                <lb/>
              che biſognaua mostrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.471.0.0" type="head">
              <s id="id.2.1.471.1.0">COROLLARIO I. </s>
            </p>
            <p id="id.2.1.472.0.0" type="main">
              <s id="id.2.1.472.1.0">Da queſto è chiaro ancora, come prima, che ſe ſarà poſto il pe­
                <lb/>
              ſo più vicino al ſoſtegno B, come in H, il peſo douerſi ſo­
                <lb/>
              ſtenere da forza minore. </s>
            </p>
            <p id="id.2.1.473.0.0" type="main">
              <s id="id.2.1.473.1.0">
                <emph type="italics"/>
              Percioche HB ha proportione minore à BD, che AB à BD. </s>
              <s id="N1386E">& quanto più
                <emph.end type="italics"/>
                <arrow.to.target n="note136"/>
                <lb/>
                <emph type="italics"/>
              da vicino ſarà al ſoſtegno, ſempre anco minore forza vi ſi ricercherà.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.474.0.0" type="margin">
              <s id="id.2.1.474.1.0">
                <margin.target id="note136"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              8.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.475.0.0" type="head">
              <s id="id.2.1.475.1.0">COROLLARIO II. </s>
            </p>
            <p id="id.2.1.476.0.0" type="main">
              <s id="id.2.1.476.1.0">Egli è parimente manifeſto, che la poſſanza in D è ſempre
                <lb/>
              maggiore del peſo C. </s>
            </p>
            <p id="id.2.1.477.0.0" type="main">
              <s id="id.2.1.477.1.0">
                <emph type="italics"/>
              Perche ſe tra AB ſi piglia qual ſi voglia punto, come D, ſempre AB ſarà mag
                <lb/>
              giore di BD.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.478.0.0" type="main">
              <s id="id.2.1.478.1.0">
                <emph type="italics"/>
              El è da auertire, che queſte dimoſtrationi lequali habbiamo prodotte in mezo, ſi poſſo­
                <lb/>
              no à tutte queſte coſe commodamente adattare non ſolamente eſſendo le leue egual­
                <lb/>
              mente distanti dall'orizonte, ma anche inchinate le dette leue all'orizonte. </s>
              <s id="id.2.1.478.2.0">ilche è
                <lb/>
              chiaro da quel che nella bilancia ſi è diuiſato.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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