Salusbury, Thomas
,
Mathematical collections and translations (Tome I)
,
1667
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of the Circumſcribed and inſcribed Figures: and that it's poſſible, that
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there be a Line in the middle betwixt thoſe Centers that is leſs than any
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Line aſſigned; it followeth that the ſame given Line be much leſs that
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lyeth betwixt one of the ſaid Centers and the ſaid point that divides
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the Axis.
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<
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>PROPOSITION.</
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<
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>The Center of Gravity divideth the Axis of any
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Cone or Pyramid ſo, that the part next the
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Vertex is triple to the remainder.</
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Let there be a Cone whoſe Axis is A B. </
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>And in C let it be divided,
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ſo that A C be triple to the remaining part C B. </
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>It is to be proved,
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that C is the Center of Gravity of the Cone. </
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>For if it be not, the
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Cone's Center ſhall be either above or below the point C. </
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>Let it be firſt
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beneath, and let it be E. </
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>And draw the Line L P, by it ſelf, equal to
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C E; which divided at pleaſure in N. </
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>And as both B E and P N to
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gether are to P N, ſo let the Cone be to the Solid X: and inſcribe in the
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Cone a Solid Figure of Cylinders that have equal Baſes, whoſe Center
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of Gravity is leſs diſtant from the point C than is the Line L N, and
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the exceſs of the Cone above it leſs than the Solid X. </
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<
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>And that this
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may be done is manifeſt from what hath been already demonſtrated.
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<
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>Now let the inſcribed Figure be ſuch as
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was required, whoſe Center of Gravity
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let be I. </
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>The Line I E therefore ſhall be
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greater than N P together with L P. </
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<
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>Let
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C E and I C leſs L N be equal: And be
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cauſe both together B E and N P is to N P
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as the Cone to X: and the exceſs by which
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the Cone exceeds the inſcribed Figure is
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leſs than the Solid X: Therefore the Cone
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ſhall have greater proportion to the ſaid
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X S than both B E and N P to N P: and, by
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Diviſion, the inſcribed Figure ſhall have
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greater proportion to the exceſs by which
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the Cone exceeds it, than B E to N P: But B E hath leſs proportion to
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E I than to N P with I E. </
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<
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>Let N P be greater. </
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<
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>Then the inſcribed Fi
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gure hath to the exceſs of the Cone above it much greater proportion
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than B E to E I. </
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<
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>Therefore as the inſcribed Figure is to the ſaid exceſs,
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ſo ſhall a Line bigger than B E be to E I. </
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<
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>Let that Line be M E. Becauſe,
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therefore, M E is to E I as the inſcribed Figure is to the exceſs of the
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Cone above the ſaid Figure, and D is the Center of Gravity of the
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Cone, and I the Center of Gravity of the inſcribed Figure: Therefore
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