Harriot, Thomas
,
Mss. 6785
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(9v)
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(10)
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<
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<
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<
p
xml:lang
="
lat
">
<
s
xml:space
="
preserve
"> Iisdem positis: In linea
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
sumatur quovis punctum
<
math
>
<
mstyle
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
<
lb
/>
et erigatur perpendicularis
<
math
>
<
mstyle
>
<
mi
>o</
mi
>
<
mi
>n</
mi
>
</
mstyle
>
</
math
>
quæ erit parallela lineaæ
<
lb
/>
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>h</
mi
>
</
mstyle
>
</
math
>
et secabit lineam
<
math
>
<
mstyle
>
<
mi
>h</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
in puncto
<
math
>
<
mstyle
>
<
mi
>n</
mi
>
</
mstyle
>
</
math
>
. agatur etiam recta
<
lb
/>
<
math
>
<
mstyle
>
<
mi
>n</
mi
>
<
mi
>a</
mi
>
</
mstyle
>
</
math
>
, quæ secabit
<
math
>
<
mstyle
>
<
mi
>g</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
in puncto
<
math
>
<
mstyle
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
.
<
emph
style
="
st
">Manifestum est</
emph
>
<
lb
/>
[
<
emph
style
="
bf
">Translation: </
emph
>
The same things being supposed, in the line
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
there is taken any point
<
math
>
<
mstyle
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
and there is constructed the perpendicular
<
math
>
<
mstyle
>
<
mi
>o</
mi
>
<
mi
>n</
mi
>
</
mstyle
>
</
math
>
which will be parallel to the line
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>h</
mi
>
</
mstyle
>
</
math
>
and will cut the line
<
math
>
<
mstyle
>
<
mi
>h</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
in the point
<
math
>
<
mstyle
>
<
mi
>n</
mi
>
</
mstyle
>
</
math
>
. There is also constructed the line
<
math
>
<
mstyle
>
<
mi
>n</
mi
>
<
mi
>a</
mi
>
</
mstyle
>
</
math
>
, which will cut
<
math
>
<
mstyle
>
<
mi
>g</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
in the point
<
math
>
<
mstyle
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
. </
s
>
</
p
>
<
p
xml:lang
="
lat
">
<
s
xml:space
="
preserve
"> Dico primo quod
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
est maior quam
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
.
<
lb
/>
connectantur puncta
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
,
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
,
<
lb
/>
et fiat
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>p</
mi
>
</
mstyle
>
</
math
>
æqualis lineæ
<
math
>
<
mstyle
>
<
mi
>n</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
<
lb
/>
sitque acta recta
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
quæ
<
lb
/>
<
emph
style
="
super
">necessario</
emph
>
secabit lineam
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
in puncto
<
math
>
<
mstyle
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
.
<
lb
/>
<
emph
style
="
st
">Quoniam</
emph
>
<
emph
style
="
super
">et
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>z</
mi
>
</
mstyle
>
</
math
>
in puncto
<
math
>
<
mstyle
>
<
mi
>q</
mi
>
</
mstyle
>
</
math
>
.</
emph
>
Quoniam
<
lb
/>
In triangulo
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
, latera
<
lb
/>
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
sunt æqualia,
<
lb
/>
anguli etiam ad
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
<
lb
/>
sunt etiam
<
lb
/>
[
<
emph
style
="
bf
">Translation: </
emph
>
I say first that
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
is greater than
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
.
<
lb
/>
Connect the points
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
and
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
, and make
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>p</
mi
>
</
mstyle
>
</
math
>
equal to the line
<
math
>
<
mstyle
>
<
mi
>n</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
; let there also be constructed the line
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
which will necessarily cut the line
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
in the point
<
math
>
<
mstyle
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
and
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>z</
mi
>
</
mstyle
>
</
math
>
in the point
<
math
>
<
mstyle
>
<
mi
>q</
mi
>
</
mstyle
>
</
math
>
. Because in the triangle
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
, the sides
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
and
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
are equal, and also the angles at
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
and
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
are also equal. </
s
>
</
p
>
<
p
xml:lang
="
lat
">
<
s
xml:space
="
preserve
"> Sed angulus ad
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
nempe
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
hoc est
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
est
<
lb
/>
æqualis duobus angulis interioris
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>s</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
. Duobus videlicet
<
lb
/>
interioris et oppositis triangulis
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
. Ergo maior est
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
anguli,
<
lb
/>
maior etiam angulo
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>r</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
qui
<
emph
style
="
super
">est</
emph
>
ad verticem
<
lb
/>
anguli
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
. Ergo, angulos
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
hoc est
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
est
<
lb
/>
maior quam angulus
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>r</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
. Ergo
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
lineam est maior quam
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
.
<
lb
/>
multo igitur maior
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>q</
mi
>
</
mstyle
>
</
math
>
quam
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
. Sed linea
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>q</
mi
>
</
mstyle
>
</
math
>
, æqualis est
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
<
lb
/>
ergo
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
est maior quam
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
. Sed etiam
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
est æqualis
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
, cum
<
lb
/>
sunt latera subtendentia æqualis angulos æqualium triangulum
<
lb
/>
nempe,
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
<
mi
>s</
mi
>
<
mi
>p</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>o</
mi
>
<
mi
>n</
mi
>
<
mi
>p</
mi
>
</
mstyle
>
</
math
>
. Ergo
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
est maior quam
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
, quod primo
<
lb
/>
demonstrandum
<
lb
/>
[
<
emph
style
="
bf
">Translation: </
emph
>
But the angle at
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
, namely
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
, that is
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
is equal to two interior angles
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>s</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
, clearly the two interior and opposite angles in triangle
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
. Therefore
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
is the greater angle.
<
lb
/>
The angle
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>r</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
is also greater, which is at the vertex of angle
<
math
>
<
mstyle
>
<
mi
>t</
mi
>
<
mi
>r</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
. Therefore, the angle
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>d</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
, that is
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
, is greater than the angle
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>r</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
. Therefore the line
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>r</
mi
>
</
mstyle
>
</
math
>
is greater than
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
, and therefore
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>q</
mi
>
</
mstyle
>
</
math
>
is much greater than
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
. But the line
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>q</
mi
>
</
mstyle
>
</
math
>
is equal to
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
, therefore
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
is greater than
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
. But also
<
math
>
<
mstyle
>
<
mi
>p</
mi
>
<
mi
>d</
mi
>
</
mstyle
>
</
math
>
is equal to
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
, since they are sides subtending equal angles of equal triangles, namely,
<
math
>
<
mstyle
>
<
mi
>d</
mi
>
<
mi
>s</
mi
>
<
mi
>p</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>o</
mi
>
<
mi
>n</
mi
>
<
mi
>a</
mi
>
</
mstyle
>
</
math
>
. Therefore
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
is greater than
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>o</
mi
>
</
mstyle
>
</
math
>
, which was to be demonstrated first. </
s
>
</
p
>
<
p
xml:lang
="
lat
">
<
s
xml:space
="
preserve
"> Dico secundo, ut
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
ad
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
, seu ut
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
ad
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>h</
mi
>
</
mstyle
>
</
math
>
, ita
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
ad
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>n</
mi
>
</
mstyle
>
</
math
>
.
<
lb
/>
Hoc enim manifestum ex similitudine triangulorum
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>s</
mi
>
<
mi
>u</
mi
>
</
mstyle
>
</
math
>
,
<
lb
/>
seu
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
et
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>n</
mi
>
<
mi
>h</
mi
>
</
mstyle
>
</
math
>
<
lb
/>
[
<
emph
style
="
bf
">Translation: </
emph
>
I say, second, that as
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
</
mstyle
>
</
math
>
to
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>s</
mi
>
</
mstyle
>
</
math
>
, or as
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
to
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>h</
mi
>
</
mstyle
>
</
math
>
, so is
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
to
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>n</
mi
>
</
mstyle
>
</
math
>
.
<
lb
/>
For this is clear from the similarity of triangles
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>t</
mi
>
<
mi
>e</
mi
>
</
mstyle
>
</
math
>
and
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>s</
mi
>
<
mi
>u</
mi
>
</
mstyle
>
</
math
>
, or
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>e</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
and
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>n</
mi
>
<
mi
>h</
mi
>
</
mstyle
>
</
math
>
. </
s
>
</
p
>
</
div
>
</
text
>
</
echo
>