Harriot, Thomas, Mss. 6785

List of thumbnails

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201 (101) 		202
202 (101v)
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203 (102) 		204
204 (102v)
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205 (103) 		206
206 (103v)
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207 (104) 		208
208 (104v)
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209 (105) 		210
210 (105v)
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page |< < (119) of 882 > >|
    <echo version="1.0RC">
      <text xml:lang="eng" type="free">
        <div type="section" level="1" n="1">
          <pb file="add_6785_f119" o="119" n="237"/>
          <head xml:space="preserve" xml:lang="lat"> Canon universalis, pro superficie cuislibet
            <lb/>
          polygoni
            <lb/>
          [
            <emph style="bf">Translation: </emph>
          A general rule for the surface of any spherical ]</head>
          <p xml:lang="lat">
            <s xml:space="preserve"> Omne polygonon est triangulum vel ex triangulis compositum. &c.
              <lb/>
            Unde canon
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Every polygon is a triangle or composed from triangles, etc.
              <lb/>
            Hence the general ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> Adde omnes angulos cuislibet polygoni simul, qui sunt omnes anguli
              <lb/>
            triangulorum ex quibus constat
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Add all the angles of any polygons together, which are all the angles of the triangles from which the polygon is ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> A summa subtrahe toties 180: quoties polygonon continet
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            From the sum subtract 180 as many times as the polygon contains ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> Dimidium reliqui æquali est polygono, vel omnibus triangulis
              <lb/>
            quibus constat
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Half the remainder is equal to the polygon, or all to all the triangles from which the polygon is ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> Breviter sic:
              <lb/>
            Adde omnes angulos cuislibet polygoni simul:
              <lb/>
            A summa subtrahe toties 190: quoties possibile:
              <lb/>
            Dimidium Reliqui æquale est superficiei
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            More briefly thus:
              <lb/>
            Add all the angles of any polygon simultaneously.
              <lb/>
            From the sum subtract 180 as many times as possible.
              <lb/>
            Half the remainder is equal to the surface of the ]</s>
          </p>
        </div>
      </text>
    </echo>
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