Harriot, Thomas, Mss. 6785

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757379
[Commentary:
The reference on this page is to the Lemma of Monachos, as found in Proposition 59 of Commandino's edition of Pappus Mathematicae collectiones (Pappus .
Theorema LVI. Propositio LIX.
Semicirculo existente AEB, & diametro AB, existentibusque perpendicularibus CE & ducta recta linea EFG, & ad ipsam perpendiculari BG, tria porro contingunt, videlicet rectangulum quidem CBD aequale esse quadrato ex BG; rectangulum vero contentum AC BD quadrato ex FG, & contentum AD CB quadrato ex

Given a semicircle AEB with diameter AB, and perpendiculars CE, DF, and having drawn the line EFG, and the perpendicular to it, BG, then three things come about, namely, the rectangle CB.BD is equal to the square of BG; and the rectangle AC.BD to the square of FG, and teh rectangle AD.CB to the square of EG.
Harriot's note about the diagram is difficult to read. In the diagram given by CE and DF are symmetrically placed about the centre so that EG is parallel to AB. Harriot's diagram is therefore more general. ]
In Monachos lemma.
prop. 59. lib. 7. pappi. pag.
[Translation: On the lemma of Monachos, Proposition 59, Book 7 of Pappus, page ]
Data seu posita
AEB semicirculo
AB. Diameter.
cui CE, DF, perpendiculares.
EFG producta
cui BG perpendic-

[Translation: Given or supposed, a semicircle AEB with diameter AB, to which CE and DF are perpendiculars, and EFG extended, to which BG is a perpendicular.
Diagrapha [???]
in Græco [???]
et apud
[Translation: Diagram [???]
in the Greek [???]
and in ]
Tria
Consequentia
[Translation: Three consequences to be ]
Constructiones seu linearum ductiones
[…]
Consequentia ex ductis et constructis.
[…]
quia puncta D, B, G, F, sunt in circulo.
quia super eadem peripheriam.
quia C, E, G, B, sunt in circulo. EB [???]
diameter.
[…]
Tum: Traing. DGB et CGB sunt æquiangula. quia CBG communis utrisque.
[…]
Prima
[Translation: Construction ordrawing of the lines

Consequence from the drawing and ex ductis construction.

becasue the opoints D, B, G, F are on a circle.
because on the same circumference.
because C, E, G, B are on a circle. EB [???] diameter.

Then triangles DGB et CGB are equiangular because CBG is common to both.

First ]
per primam consequens.
2
[Translation: by the first consequence
Consequence ]
per primam consequens.
3.
[Translation: by the first consequence
Consequence ]
AG, ED, AD, non necessario
et AE omissa. apud
Commandinum.
AD etiam superflua.
Malo etiam in
[Translation: AG, ED, AD are not necessary and AE is omitted by Commandino.
AD is also superfluous.
Also badly done in the ]

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