Salusbury, Thomas
,
Mathematical collections and translations (Tome I)
,
1667
Text
Text Image
Image
XML
Thumbnail overview
Document information
None
Concordance
Figures
Thumbnails
page
|<
<
of 701
>
>|
<
archimedes
>
<
text
>
<
body
>
<
chap
>
<
p
type
="
main
">
<
s
>
<
pb
xlink:href
="
040/01/1046.jpg
"
pagenum
="
351
"/>
nue, but will return to be according to the
<
lb
/>
<
figure
id
="
id.040.01.1046.1.jpg
"
xlink:href
="
040/01/1046/1.jpg
"
number
="
240
"/>
<
lb
/>
Perpendieular. </
s
>
<
s
>It is manifeſt that the Gen
<
lb
/>
tre of the Sphære is in the Line F T. </
s
>
<
s
>And
<
lb
/>
again, foraſmuch as the Portion of a Sphære
<
lb
/>
may be greater or leſſer than an Hemiſ
<
lb
/>
phære, and may alſo be an Hemiſphære, let
<
lb
/>
the Centre of the Sphære in the Hemiſ
<
lb
/>
phære be the Point T, & in the leſſer Por
<
lb
/>
tion the Point P, and in the Greater the </
s
>
</
p
>
<
p
type
="
main
">
<
s
>
<
arrow.to.target
n
="
marg1157
"/>
<
lb
/>
Point R. </
s
>
<
s
>And ſpeaking firſt of that greater
<
lb
/>
Portion which hath its Baſe within the
<
lb
/>
Liquid, thorow R and L, the Earths Cen
<
lb
/>
<
figure
id
="
id.040.01.1046.2.jpg
"
xlink:href
="
040/01/1046/2.jpg
"
number
="
241
"/>
<
lb
/>
tre, draw the line RL. </
s
>
<
s
>The Portion that is
<
lb
/>
above the Liquid, hath its Axis in the Per
<
lb
/>
pendicular paſſing thorow R; and by
<
lb
/>
what hath been ſaid before, its Centre of
<
lb
/>
Gravity ſhall be in the Line N R; let it
<
lb
/>
be the Point R: But the Centre of Gra
<
lb
/>
vity of the whole Portion is in the line F
<
lb
/>
T, betwixt R and F; let it be X: The re
<
lb
/>
mainder therefore of that Figure, which is
<
lb
/>
within the Liquid ſhall have its Centre in
<
lb
/>
the Right Line R
<
emph
type
="
italics
"/>
X
<
emph.end
type
="
italics
"/>
prolonged in the part
<
lb
/>
<
figure
id
="
id.040.01.1046.3.jpg
"
xlink:href
="
040/01/1046/3.jpg
"
number
="
242
"/>
<
lb
/>
towards
<
emph
type
="
italics
"/>
X,
<
emph.end
type
="
italics
"/>
taken ſo, that the part pro
<
lb
/>
longed may have the ſame Proportion to
<
lb
/>
X R, that the Gravity of the Portion that
<
lb
/>
is above the Liquid hath to the Gravity
<
lb
/>
of the Figure that is within the Liquid.
<
lb
/>
</
s
>
<
s
>Let O be the Centre of that ſame Figure:
<
lb
/>
and thorow O draw the Perpendicular L
<
lb
/>
O. </
s
>
<
s
>Now the Gravity of the Portion that
<
lb
/>
is above the Liquid ſhall preſs according
<
lb
/>
to the Right Line R L downwards; and
<
lb
/>
the Gravity of the Figure that is in the
<
lb
/>
Liquid according to the Right Line O L upwards: There the Figure
<
lb
/>
ſhall not continue; but the parts of it towards H ſhall move down
<
lb
/>
wards, and thoſe towards E upwards: &
<
lb
/>
<
figure
id
="
id.040.01.1046.4.jpg
"
xlink:href
="
040/01/1046/4.jpg
"
number
="
243
"/>
<
lb
/>
this ſhall ever be, ſo long as F T is accord
<
lb
/>
ing to the Perpendicular.</
s
>
</
p
>
<
p
type
="
margin
">
<
s
>
<
margin.target
id
="
marg1157
"/>
A</
s
>
</
p
>
<
p
type
="
head
">
<
s
>COMMANDINE.</
s
>
</
p
>
<
p
type
="
main
">
<
s
>The Portion that is above the Liquid
<
lb
/>
<
arrow.to.target
n
="
marg1158
"/>
<
lb
/>
hath its Axis in the Perpendicular paſſing
<
lb
/>
thorow K.]
<
emph
type
="
italics
"/>
For draw B C cutting the Line N K in
<
lb
/>
M; and let N K out the Circumference
<
emph.end
type
="
italics
"/>
A B
<
emph
type
="
italics
"/>
C D in G. </
s
>
<
s
>In
<
lb
/>
the ſame manner as before me will demonſtrate, that the Axis
<
emph.end
type
="
italics
"/>
</
s
>
</
p
>
</
chap
>
</
body
>
</
text
>
</
archimedes
>