DelMonte, Guidubaldo, In duos Archimedis aequeponderantium libros Paraphrasis : scholijs illustrata

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    <archimedes>
      <text>
        <body>
          <chap id="N10019">
            <pb xlink:href="077/01/104.jpg" pagenum="100"/>
            <p id="N13AFA" type="margin">
              <s id="N13AFC">
                <margin.target id="marg136"/>
                <emph type="italics"/>
              ex
                <emph.end type="italics"/>
              4.
                <emph type="italics"/>
              ſexti
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13B0A" type="margin">
              <s id="N13B0C">
                <margin.target id="marg137"/>
              11.
                <emph type="italics"/>
              quinti.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13B15" type="margin">
              <s id="N13B17">
                <margin.target id="marg138"/>
              16.
                <emph type="italics"/>
              quinti.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.077.01.104.1.jpg" xlink:href="077/01/104/1.jpg" number="64"/>
            <p id="N13B24" type="head">
              <s id="N13B26">
                <emph type="italics"/>
              IDEM ALITER.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13B2C" type="main">
              <s id="N13B2E">
                <emph type="italics"/>
              Sit triangulum ABC, ducaturquè AD
                <emph.end type="italics"/>
              ab angulo A
                <emph type="italics"/>
              ad
                <expan abbr="dimidiã">dimidiam</expan>
                <emph.end type="italics"/>
                <lb/>
              baſim
                <emph type="italics"/>
              BC. Dico in linea AD centrum eſſe grauitatis trianguli ABC.
                <lb/>
              N on ſit autem, ſed ſi fieri poteſt; ſit H. iunganturquè AH HB HC, &
                <lb/>
              ED
                <emph.end type="italics"/>
              DF
                <emph type="italics"/>
              FE ad dimidias BA
                <emph.end type="italics"/>
              BC
                <emph type="italics"/>
              AC
                <emph.end type="italics"/>
              ducantur, ſecetquè EF ip­
                <lb/>
              ſam AD in M. &
                <emph type="italics"/>
              ipſi AH æquidistantes ducantur EK FL. &
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="fig46"/>
                <lb/>
                <emph type="italics"/>
              iungantur KL LD Dk DH
                <emph.end type="italics"/>
              ; ſecetquè DH ipſam KL in N.
                <lb/>
              iungaturquè
                <emph type="italics"/>
              MN. Quoniam igitur triangulum ABC ſimile est
                <expan abbr="triã">triam</expan>
                <lb/>
              gulo DFC, cùm ſit BA ipſi FD æquidistans
                <emph.end type="italics"/>
              ; ſiquidem ſunt late­
                <lb/>
                <arrow.to.target n="marg139"/>
              ra CA CB bifariam diuiſa, ideoquè ſit CF ad FA, vt CD
                <lb/>
              ad DB.
                <emph type="italics"/>
              trianguliquè ABC centrum grauitatis est punctum H; &
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="marg140"/>
                <emph type="italics"/>
              trianguli FDC centrum grauitatis erit punctum L. puncta enim HB
                <lb/>
              intra vtrumquè triangulum ſunt ſimiliter poſita. </s>
              <s id="N13B8E">etenim ad homologa
                <lb/>
              latera angulos efficiunt æquales. </s>
              <s id="N13B92">hoc enim perſpicuum. </s>
              <s id="N13B94">est
                <emph.end type="italics"/>
              cùm enim
                <lb/>
              ſint triangulorum ABC DFC homologa latera AC FC,
                <lb/>
                <arrow.to.target n="marg141"/>
              AB FD, BC DC, ſintquè AH FL æquidiſtantes; erit an­
                <lb/>
              gulus LFC angulo HAC ęqualis. </s>
              <s id="N13BA3">ſed angulus CFD eſt ipſi </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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