DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N106DF">
            <pb pagenum="4" xlink:href="037/01/023.jpg"/>
            <p id="id.2.1.93.0.0" type="main">
              <s id="id.2.1.93.1.0">
                <emph type="italics"/>
              Come, poſte le coſe iſteſſe, ſia ſoſtenuto
                <lb/>
              il peſo dalle linee CG CH. </s>
              <s id="id.2.1.93.2.0">Dico
                <lb/>
              che ſe la tirata linea BC ſarà à
                <lb/>
              piombo dell'orizonte, il peſo ſtarà
                <lb/>
              fermo: ma ſe la tirata linea CF
                <lb/>
              non ſarà à piombo dell'orizonte, il
                <lb/>
              punto F ſimouerà in giù fin al D,
                <lb/>
              nel qual ſito ſtarà fermo il peſo,
                <lb/>
              & la tirata linea CD ſarà à piom­
                <lb/>
              bo dell'orizonte. </s>
              <s id="id.2.1.93.3.0">Le quali coſe
                <lb/>
              tutte con la ragione medeſima ſi pro­
                <lb/>
              uerebbono.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.037.01.023.1.jpg" xlink:href="037/01/023/1.jpg" number="6"/>
            <p id="id.2.1.95.0.0" type="head">
              <s id="id.2.1.95.1.0">PROPOSITIONE II. </s>
            </p>
            <p id="id.2.1.96.0.0" type="main">
              <s id="id.2.1.96.1.0">La bilancia egualmente diſtante dall'orizonte, il cui centro ſtia ſopra
                <lb/>
              la detta bilancia, & che habbia i peſi eguali nelle ſtremità, & egual­
                <lb/>
              mente diſtanti dal perpendicolo, ſe da cotale ſito ſarà moſſa, &
                <lb/>
              nell'iſteſſo di nuouo laſciata, ritornerà, & iui reſterà. </s>
            </p>
            <figure id="id.037.01.023.2.jpg" xlink:href="037/01/023/2.jpg" number="7"/>
            <p id="id.2.1.98.0.0" type="main">
              <s id="id.2.1.98.1.0">
                <emph type="italics"/>
              Sia la bilancia AB in
                <lb/>
              linea diritta egualmen
                <lb/>
              te diſtante dall'orizon
                <lb/>
              te, il cui centro C ſia
                <lb/>
              ſopra la bilancia, &
                <lb/>
              ſia CD il perpendi­
                <lb/>
              colo, il quale ſarà à
                <lb/>
              piombo dell'orizonte:
                <lb/>
              & la diſtanza DA
                <lb/>
              ſia eguale alla diſtan­
                <lb/>
              za DB: & ſiano i
                <lb/>
              peſi in AB eguali,
                <lb/>
              i centri della grauez­
                <lb/>
              za de' quali ſiano ne i
                <lb/>
              punti AB. </s>
              <s id="id.2.1.98.2.0">Mouaſi
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              da queſto ſito la bi­
                <lb/>
              lancia AB come in EF, dapoi ſia laſciata. </s>
              <s id="id.2.1.98.3.0">Dico che la bilancia EF ritor­
                <lb/>
              neràin AB diſtante egualmente dall'orizonte, & iui rimanerà. </s>
              <s id="id.2.1.98.4.0">Hora percioche
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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