Archimedes
,
Natation of bodies
,
1662
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the Angles at X and N are equall. </
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<
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>And, therefore, if drawing HK,
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it be prolonged to
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the Centre of Gravity of the whole Portion ſhall
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be K; of the part which is within the Liquid H; and of the part which
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is above the Liquid in K
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as ſuppoſe in
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and H K perpendicular to
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the Surface of the Liquid. </
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<
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>Therfore
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along the ſame Right Lines ſhall the
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part which is within the Liquid move
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upwards, and the part above it down
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wards: And therfore the Portion
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ſhall reſt with one of its Points
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touching the Surface of the Liquid,
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and its Axis ſhall make with the
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ſame an Angle equall to X. </
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<
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>It is
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to be demonſtrated in the ſame
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manner that the Portion that hath
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the ſame proportion in Gravity to the Liquid, that the Square P F hath
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to the Square B D, being demitted into the Liquid, ſo, as that its
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Baſe touch not the Liquid, it ſhall ſtand inclined, ſo, as that its Baſe
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touch the Surface of the Liquid in one Point only; and its Axis ſhall
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make therwith an Angle equall to the Angle
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A</
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B</
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C</
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D</
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E</
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F</
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<
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>COMMANDINE.
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<
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<
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A</
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<
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<
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>That is the Square T P to the Square B D.]
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By the twenty ſixth of the Book
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<
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of
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Archimedes, De Conoidibus & Sphæroidibus:
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Therefore, (a) the Square T P
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ſhall be equall to the Square X O: And for that reaſon, the Line T P equall to the
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Line X O.
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<
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(a)
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By 9 of the
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fifth.
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B</
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</
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<
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<
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>The Portions ſhall alſo be equall.]
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By the twenty fifth of the ſame Book.
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</
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</
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<
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<
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<
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C</
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<
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>Again, becauſe that in the Equall and Like Portions, A O Q L
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and A P M L.]
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For, in the Portion A P M L, deſcribe the Portion A O Q equall
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to the Portion I P M: The Point Q falleth beneath M; for otherwiſe, the Whole would be
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equall to the Part. </
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<
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>Then draw I V parallel to A Q, and cutting the Diameter is
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and
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let I M cut the ſame
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and A Q in
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<
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">ς.</
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I ſay
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that the Angle A
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D, is leſſer than the Angle
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<
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I
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<
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D. </
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<
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>For the Angle I
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D is equall to the
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Angle A
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<
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<
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D: (b) But the interiour Angle
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</
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<
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I
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D is leſſer than the exteriour I
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<
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">σ</
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<
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D: There-
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<
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fore, (c) A
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<
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D ſhall alſo be lefter than I
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<
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<
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D.
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<
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(b)
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By 29 of the
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firſt.
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<
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(c) By 16 of the
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firſt.
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</
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<
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<
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D</
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<
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<
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>And the Angle at X, being leſſe
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than the Angle at N.]
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Thorow O draw twe
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Lines, O C perpendicular to the Diameter B D, and
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O X touching the Section in the Point O, and cutting
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</
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</
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<
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the Diameter in X: (d) O X ſhall be parallel
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to A
<
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abbr
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">que</
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>
and the
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(e)
<
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Angle at X, ſhall be equall to
<
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<
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<
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that at
<
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<
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">υ</
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>
:
<
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Therefore, the
<
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"/>
(f)
<
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"/>
Angle at X,
<
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<
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<
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ſhall be leſſer than the Angle at
<
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="
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<
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">ς;</
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>
<
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that is, to
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that at N: And, conſequently, X ſhall fall beneath N: Therefore, the Line X B is greater than
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N B. And, ſince B C is equall to X B, and B S equall to N B; B C ſhall be greater than B S.
<
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