Biancani, Giuseppe, Aristotelis loca mathematica, 1615

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1
Problema Primum.
Cur oriente, aut occumbente Sole, Iris ſemicirculus eſt?
Cauſa huius hæc eſt; ſupra enim dictum eſt, in omni Iridis appari­
tione tria hæc, Solem, oculum, & Iridis centrum eſſe in eadem re­
cta linea, v. g. in linea A C D, præcedentis figuræ, cum igitur Sol
tam oriens, quam occidens ſit in horizonte, v. g. in A, horizontis
puncto, ſimiliter oculus ſit in C, horizontis centro, conſectarium eſt, cen­
trum etiam Iridis D, eſſe pariter in horizontis ſuperficie, quare ſecabitur
ab horizonte per centrum, vnde etiam ſequitur ipſius Iridis portionem
E B F, quæ ſupra horizontem extat eſſe ſemicirculum.
Quod ſi horizon non
obſtaret, integrum Iris compleret orbem, cernereturque; toto ambitu B F M E.
An quandoque; maior ſemicirculo appareat?
Problema Secundum.
Maior quidem, imò etiam integer circulus, ſed ab oculo in ſummitate
montis conſtituto, Soleque; iam multum eleuato videri poteſt, vt in
hac ſecunda figura cernitur, vbi euecto Sole ad locum E, ſupra horizontem
66[Figure 66]
A B, poterit oculus in vertice montis C, poſitus Iridem F G H I, comple­
tam videre, quia infra lineam E C D, in qua exiſtunt Sol, oculus, & Iridis
centrum, nihil eſt ad partes D, vbi nubes irrorat, quod Iridis apparitioni
ſit impedimento.

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