Galilei, Galileo, Les méchaniques, 1634

Table of figures

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            <p type="main">
              <s id="s.000245">
                <pb pagenum="52" xlink:href="047/01/072.jpg"/>
                <expan abbr="inclinatiõs">inclinations</expan>
              des
                <expan abbr="plãs">plans</expan>
              FB, LB &c. </s>
              <s id="s.000246">de ſorte
                <lb/>
              que l'on peut s'imaginer la deſcente de
                <lb/>
              C par tous les points du quart de cercle
                <lb/>
              CI, lequel contient vn plan qui s'incli­
                <lb/>
              ne perpetuellement de plus en plus,
                <lb/>
              & que la peſanteur du poids en C eſt
                <lb/>
              totale & entiere, & conſequemment
                <lb/>
              qu'il ſe porte de toute ſon inclination à
                <lb/>
              deſcendre, parce qu'il n'eſt nullement
                <lb/>
              empeſché par la
                <expan abbr="circonferẽce">circonference</expan>
              , lors qu'il
                <lb/>
              ſe rencontré ſur la tangente DCE. </s>
            </p>
            <p type="main">
              <s id="s.000247">Mais quand il eſt en F, il eſt en partie
                <lb/>
              ſouſtenu par le plan circulaire, & ſa
                <lb/>
              pente, ou l'inclination qu'il a vers le
                <lb/>
              centre de la terre eſt autant diminuée
                <lb/>
              que BC ſurpaſſe BK: de maniere qu'il
                <lb/>
              ſe tient éleué ſur ce plan de meſme que
                <lb/>
              s'il eſtoit appuyé ſur la tangente GFH,
                <lb/>
                <expan abbr="d'autãt">d'autant</expan>
              que le point d'inclination F de
                <lb/>
              la circonference CI ne differe point de
                <lb/>
              l'inclination de la tangente GFH, que
                <lb/>
              par l'angle inſenſible du contact. </s>
            </p>
            <p type="main">
              <s id="s.000248">Il faut dire la meſme choſe du point
                <lb/>
              L, lequel eſt incliné comme s'il eſtoit
                <lb/>
              ſur le plan de la tangeule NLO, car il
                <lb/>
              diminuë ſa pente, & ſon
                <expan abbr="inclinatiõ">inclination</expan>
              qu'il
                <lb/>
              a en C en meſme proportion que Bk eſt
                <lb/>
              à BC, puis qu'il eſt conſtant par la </s>
            </p>
          </chap>
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      </text>
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