<s id="A18-1.31.01">[31] Let now another, also even and evenly heavy, load be given, namely <ab>, which rests on supports in the same position, namely <ag> and <bd>.</s>
<s id="A18-1.31.02">Then it is clear that on each of the supports falls half of the load <ab>.</s>
<s id="A18-1.31.03">Let us now suspend a weight from <ab> at point <e>.</s>
<s id="A18-1.31.04">If point <e> divides <ab> equally, then it is clear that to each of the supports falls half of the load <ab> and half of the weight suspended or put on at point <e>.</s>
<s id="A18-1.31.05">If point <e> does not divide the load in half, however, and if one divides the load in the ratio of <be> and <ea>, then the weight of the part proportional to <eb> falls to <ag> and the weight of the part proportional to <ea> [falls] to <bd>, furthermore each of the supports bears half of <ab>.</s>
<s id="A18-1.31.06">If we now suspend another weight at point <z> and divide it in the ratio of <az> and <zb>, then on <db> falls the weight of the part proportional to <az> and on <ag> the weight [of the part proportional] to <zb>; and each of the supports is affected by half of <ab>.</s>
<s id="A18-1.31.07">The relation of <zb> to <ag> has just been mentioned.</s>
<s id="A18-1.31.08">The loads that affected them, before the weights attached at the points <e>, <z> were suspended, have also already been mentioned; </s>
<s id="A18-1.31.09">thus everything has been given that falls to the two supports <ag> and <bd>.</s>
<s id="A18-1.31.10">If more weights are attached, then we learn after the same method how much weight falls to each of the two supports.</s>
