<s id="A18-2.40.01">40 If a triangle <abg> is given and known weights are suspended at points <a>, <b>, <g>, we want to find in the interior of the triangle such a point that the triangle, if it is suspended at it, is in equilibrium.</s>
<s id="A18-2.40.02">We divide the line <ab> at point <d> so that <bd> relates to <ad> like the weight at <a> to the weight at <b>.</s>
<s id="A18-2.40.03">Then the point for the total weight of the two loads is at point <d>.</s>
<s id="A18-2.40.04">If we now connect the two points <d> and <g> by the line <dg> and divide it at point <e> so that <ge>relates to <ed> like the weight of <d> to the weight of <g>, then the point <e> is the point for the total weight of all and therefore the point of suspension.</s>
