<s id="A18-2.41.01">41 We want to show the same for a polygon.</s>
<s id="A18-2.41.02">Let the figure <abgde> be a polygon.</s>
<s id="A18-2.41.03">Let us suspend known weights at the points <abgde> and divide the line <ab> at point <z> so that the line <bz> relates to <za> like the weight <a> to weight <b>, then the point <z> is the center of gravity of the two weights at <a> and <b>.</s>
<s id="A18-2.41.04">Let us also divide the line <de> at point <h> so that the distance <dh> relates to <he> like the load <e> to the load <d>, then the point <h> is the point for the total weight of the two points <e>, <d>.</s>
<s id="A18-2.41.05">Let us now draw <zh> and divide it at point <q> so that (<a> + <b>) relates to (<d> + <e>) like <hq> to <qz>, then the point <q> is the point for the total weight of <abde>.</s>
<s id="A18-2.41.06">Let us yet connect the two points <g>, <q> by the line <gq> and divide it at point <k> so that <gk> relates to <kq> like the total weight of <abde> to the weight of <g>, then the point <k> is the point for the weight combined from all of them.</s>
