Baliani, Giovanni Battista, De motu naturali gravium solidorum, 1638
page |< < of 43 > >|
    <archimedes>
      <text>
        <body>
          <pb xlink:href="076/01/027.jpg"/>
          <chap>
            <p type="head">
              <s id="s.000190">PROPOSITIO XV.
                <lb/>
              </s>
            </p>
            <subchap1>
              <p>
                <s id="s.000191">Linea connectens puncta, ad quae duo gravia ab eo-
                  <lb/>
                dem puncto digressa, quorum alterum perpenden-
                  <lb/>
                ter, alterum super plano declinante descendat, simul
                  <lb/>
                perveniunt, est perpendicularis dicto plano declinanti.
                  <lb/>
                </s>
              </p>
            </subchap1>
            <p>
              <s id="s.000192">Descendant simul duo gravia a puncto A primum per-
                <lb/>
              pendiculariter in B, secundum super plano inclinato
                <lb/>
              AC, tali lege, ut simul perveniant ad puncta BD,
                <lb/>
              & ducta sit linea BD.
                <lb/>
              </s>
            </p>
            <p>
              <s id="s.000193">Dico quod dicta linea BD est perpendicularis ad AD.
                <lb/>
              </s>
            </p>
            <p>
              <s id="s.000194">Fiat AF aequalis datae AB, & AE aequalis AD, & duca-
                <lb/>
              tur EF.
                <lb/>
              </s>
            </p>
            <p>
              <s id="s.000195">Quoniam ut AD ad AB, ita AB ad AC
                <arrow.to.target n="marg34"/>
              , & AD,
                <lb/>
              AE, item AB, AF sunt aequales per constructionem, se-
                <lb/>
              quitur quod AE ad AF est ut AB ad AC, ergo EF, BC
                <lb/>
              sunt parallelae
                <arrow.to.target n="marg35"/>
              , unde triangulum AEF, & proin-
                <lb/>
              de ABD est simile triangulo ABC
                <arrow.to.target n="marg36"/>
              , unde anguli AB
                <lb/>
              C, ADB simul recti, & BD perpendicularis ad AD.
                <lb/>
              </s>
              <s id="s.000196">Quod, &c.
                <lb/>
              </s>
            </p>
            <p type="margin">
              <s id="s.000197">
                <margin.target id="marg34"/>
              Per 13.
                <lb/>
              hujus.
                <lb/>
              </s>
              <s id="s.000198">
                <margin.target id="marg35"/>
              Per 2.
                <lb/>
              Sexti.
                <lb/>
              </s>
              <s id="s.000199">
                <margin.target id="marg36"/>
              Per 4.
                <lb/>
              Sexti.
                <lb/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>