Harriot, Thomas, Mss. 6785

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              <s xml:space="preserve">[
                <emph style="bf">Commentary:</emph>
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            <p>
              <s xml:space="preserve"> On this page Harriot continues his work on Proposition VI from
                <emph style="it">Supplementum geometriæ</emph>
                <ref id="Viete_1593c" target="http://www.e-rara.ch/zut/content/pageview/2684113"> (Viète 1593c, Prop </ref>
              . See also Add MS 6785
                <ref target="http://echo.mpiwg-berlin.mpg.de/ECHOdocuView?url=/permanent/library/KN1CRTZ2/&start=260&viewMode=image&pn=269"> f. </ref>
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          <head xml:space="preserve" xml:lang="lat"> Prop. 6. Supplementi, in partem
            <lb/>
          [
            <emph style="bf">Translation: </emph>
          Proposition 6 of the Supplement, on the last ]</head>
          <p xml:lang="lat">
            <s xml:space="preserve"> Hoc est:
              <lb/>
            Quatuor continue proportionalium, quorum
              <lb/>
            prima minima:
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            Quadratum quartæ, minus quadrao primæ
              <lb/>
            Æquatur:
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            Quadrato, compositæ ex quarta
              <lb/>
            et duplæ secundæ, minus quadrato
              <lb/>
            compositæ ex prima et duplo tertiæ.
              <lb/>
            Hæc demonstrantur per
              <lb/>
            compositione altera
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            That is: for four continued proportionals, of which the first is the least, the square of the fourth minus the square of the first is equal to the square composed of the fourth and twice the second, minus the square composed of the first and twice the third.
              <lb/>
            This is demonstrated by construction on the previous ]
              <lb/>
            [
              <emph style="bf">Commentary: </emph>
            The previous sheet is Add MS
              <ref target="http://echo.mpiwg-berlin.mpg.de/ECHOdocuView?url=/permanent/library/KN1CRTZ2/&start=260&viewMode=image&pn=269"> f. </ref>
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