Harriot, Thomas
,
Mss. 6785
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20 - 29
30 - 39
40 - 49
50 - 59
60 - 69
70 - 79
80 - 89
90 - 99
100 - 109
110 - 119
120 - 129
130 - 139
140 - 149
150 - 159
160 - 169
170 - 179
180 - 189
190 - 199
200 - 209
210 - 219
220 - 229
230 - 239
240 - 249
250 - 259
260 - 269
270 - 279
280 - 289
290 - 299
300 - 309
310 - 319
320 - 329
330 - 339
340 - 349
350 - 359
360 - 369
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400 - 409
410 - 419
420 - 429
430 - 439
440 - 449
450 - 459
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510 - 519
520 - 529
530 - 539
540 - 549
550 - 559
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<
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<
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<
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<
s
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preserve
"> For the edition of Apollonius used by Harriot see
<
ref
id
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apollonius_1566
"> (Apollonius </
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>
. </
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>
<
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<
head
xml:space
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preserve
"> Mesographa
<
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Heronis.
<
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Philonis Bizantij.
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</
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<
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lat
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<
s
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preserve
"> Cum Annotatione nostra de
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faciliori
<
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[
<
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">Translation: </
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With my annotations for easier ]</
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</
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<
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>
<
s
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preserve
"> where
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>b</
mi
>
</
mstyle
>
</
math
>
is
<
lb
/>
double to
<
math
>
<
mstyle
>
<
mi
>b</
mi
>
<
mi
>c</
mi
>
</
mstyle
>
</
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>
<
lb
/>
as </
s
>
</
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>
<
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<
s
xml:space
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preserve
"> Note:
<
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/>
whether these
<
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lines be </
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>
</
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<
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<
s
xml:space
="
preserve
"> then
<
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>
<
mstyle
>
<
mi
>d</
mi
>
<
mi
>h</
mi
>
</
mstyle
>
</
math
>
would be parallel to
<
math
>
<
mstyle
>
<
mi
>a</
mi
>
<
mi
>c</
mi
>
</
mstyle
>
</
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>
<
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/>
& the problem performed nearly
<
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and also other wayes &</
s
>
</
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>
<
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>
<
s
xml:space
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"> Although Eutocius prefereth philo Bizantius his pratice of finding two
<
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/>
mean proportionalls Before that of </
s
>
<
s
xml:space
="
preserve
"> Because the number being devided
<
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into small æquall parts, it may
<
emph
style
="
super
">now</
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>
easily be seene when
<
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>
<
mstyle
>
<
mi
>h</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
&
<
math
>
<
mstyle
>
<
mi
>f</
mi
>
<
mi
>c</
mi
>
</
mstyle
>
</
math
>
be æquall,
<
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/>
then by often applying of the compasses to find
<
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>
<
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>
<
mi
>e</
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>
<
mi
>f</
mi
>
</
mstyle
>
</
math
>
&
<
math
>
<
mstyle
>
<
mi
>e</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
</
s
>
<
s
xml:space
="
preserve
"> Yet in
<
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my improvement the pratice would be better & more easy </
s
>
<
s
xml:space
="
preserve
"> Let the figures
<
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/>
nombring the æquall parts beginne at
<
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>
<
mstyle
>
<
mi
>k</
mi
>
</
mstyle
>
</
math
>
. & let their numeration runne towards
<
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>
<
mstyle
>
<
mi
>f</
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>
</
mstyle
>
</
math
>
;
<
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/>
& the like from
<
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>
<
mstyle
>
<
mi
>k</
mi
>
</
mstyle
>
</
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>
towards
<
math
>
<
mstyle
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
</
s
>
<
s
xml:space
="
preserve
"> Then will the shape of a rectangle or gnomon
<
lb
/>
keepe
<
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>
<
mstyle
>
<
mi
>k</
mi
>
<
mi
>e</
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>
</
mstyle
>
</
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>
always at rectangles with the ruler
<
math
>
<
mstyle
>
<
mi
>f</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
.
<
emph
style
="
st
">and then</
emph
>
and moving
<
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/>
the ruler with the gnomon keeping the poynt
<
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>
<
mstyle
>
<
mi
>c</
mi
>
</
mstyle
>
</
math
>
also in the line till you find
<
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/>
<
math
>
<
mstyle
>
<
mi
>k</
mi
>
<
mi
>f</
mi
>
</
mstyle
>
</
math
>
and
<
math
>
<
mstyle
>
<
mi
>k</
mi
>
<
mi
>g</
mi
>
</
mstyle
>
</
math
>
æquall; then is that performed
<
emph
style
="
st
">whi</
emph
>
also which they now have
<
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/>
&
<
emph
style
="
st
">[???]</
emph
>
<
emph
style
="
super
">thus</
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>
easier in practice because that æquallity is sooner found
<
lb
/>
<
emph
style
="
st
">because</
emph
>
the figures go
<
emph
style
="
super
">in</
emph
>
both wayes a like, which in philoes practice cannot
<
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/>
be observed but with
<
emph
style
="
st
">with</
emph
>
as much difficulty almost, if not so much as
<
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/>
that of
<
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="
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">her</
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>
</
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