Harriot, Thomas, Mss. 6785

List of thumbnails

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            <p>
              <s xml:space="preserve">[
                <emph style="bf">Commentary:</emph>
              </s>
            </p>
            <p>
              <s xml:space="preserve"> This page contains symbolic versions of Euclid's
                <ref target="http://aleph0.clarku.edu/~djoyce/java/elements/bookII/propII12.html"/>
              ,
                <ref target="http://aleph0.clarku.edu/~djoyce/java/elements/bookII/propII13.html"/>
              ,
                <ref target="http://aleph0.clarku.edu/~djoyce/java/elements/bookII/propII14.html"/>
              . </s>
              <lb/>
              <quote>
                <s xml:space="preserve">
                  <ref target="http://aleph0.clarku.edu/~djoyce/java/elements/bookII/propII12.html"/>
                In obtuse-angle triangles the square on the side opposite the obtuse angle is greater than the sum of the squares on the sides containing the obtuse angle by twice the rectangle contained by one of the sides about the obtuse angle, namely that on which the perpendicular falls, and the straight line cut off outside by the perpendicular towards the obtuse angle. </s>
              </quote>
              <lb/>
              <quote>
                <s xml:space="preserve">
                  <ref target="http://aleph0.clarku.edu/~djoyce/java/elements/bookII/propII13.html"/>
                In acute-angled triangles the square on the side opposite the acute angle is less than the sum of the squares on the sides containing the acute angle by twice the rectangle contained by one of the sides about the acute angle, namely that on which the perpendicular falls, and the straight line cut off within by the perpendicular towards the acute angle. </s>
              </quote>
              <lb/>
              <quote>
                <s xml:space="preserve">
                  <ref target="http://aleph0.clarku.edu/~djoyce/java/elements/bookII/propII14.html"/>
                To construct a square equal to a given rectilinear figure. </s>
              </quote>
              <s xml:space="preserve">]</s>
            </p>
          </div>
          <head xml:space="preserve" xml:lang="lat"> d) propositiones 2
            <emph style="super">i</emph>
            <lb/>
          [
            <emph style="bf">Translation: </emph>
          Propositions from the second book of ]</head>
          <p xml:lang="lat">
            <s xml:space="preserve"> Invenire
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            To show ]</s>
            <lb/>
            <s xml:space="preserve">
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Proposition ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> Invenire
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            To show ]</s>
            <lb/>
            <s xml:space="preserve">
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Proposition ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> p.14. et
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Proposition 14, the ]</s>
            <lb/>
            <s xml:space="preserve"> Facere quadratum, æquale
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Make a square equal to the ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> (cuiuslibet parallelogrammi rectanguli
              <lb/>
            unæqualium laterum:
              <lb/>
            si maius latus ponatur
              <math>
                <mstyle>
                  <mi>b</mi>
                  <mo>+</mo>
                  <mi>c</mi>
                </mstyle>
              </math>
              <lb/>
            minus latus erit,
              <math>
                <mstyle>
                  <mi>b</mi>
                  <mo>-</mo>
                  <mi>c</mi>
                </mstyle>
              </math>
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            For any rectangular parallelogram of unequal sides, if the longer side is supposed
              <math>
                <mstyle>
                  <mi>b</mi>
                  <mo>+</mo>
                  <mi>c</mi>
                </mstyle>
              </math>
            , the shorter will be
              <math>
                <mstyle>
                  <mi>b</mi>
                  <mo>-</mo>
                  <mi>c</mi>
                </mstyle>
              </math>
            . </s>
            <lb/>
            <s xml:space="preserve"> Finis 2
              <emph style="super">i</emph>
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            The end of the second ]</s>
          </p>
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