Harriot, Thomas, Mss. 6785

List of thumbnails

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401
401 (201)
402
402 (201v)
403
403 (202)
404
404 (202v)
405
405 (203)
406
406 (203v)
407
407 (204)
408
408 (204v)
409
409 (205)
410
410 (205v)
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          <p xml:lang="lat">
            <s xml:space="preserve"> In hoc diagrammate ut in ante-
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            cedente, sit cuiscunque sphaæraæ
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            maximus circulus
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            :
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            et axis
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            . &c.
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            A terminis laterum polgoni
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            ducantur rectæ ad centrum
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            .
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            Intelligatur superficies figuræ
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            compositæ ex conicis, ut
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            [
              <emph style="bf">Translation: </emph>
            In this diagram as in the previous ones, let any sphere have great circle
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            and axis
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            .
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            From the ends of the sides of the polygon draw the lines to the centre
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            .
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            Let it be understood that the surface of the figure is composed from cones, as ]</s>
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          <p xml:lang="lat">
            <s xml:space="preserve"> Intelligatur etiam conus
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            cuius altitudo,
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            ,
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            sit æqualis perpen-
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            diculari a centro
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            sphæræ ad latus
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            unum polygoni.
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            et basis circa diametrum
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            ,
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            Sit æqualis superficiei figuræ compositæ ex conicis.
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            Dico quod:
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            Conus = solidæ figuræ comprehensæ a dictis conicis
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            [
              <emph style="bf">Translation: </emph>
            Let there be understood also a cone whose altitude is
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            , which is equal to the perpendicular from the centre of the sphere to the side of one polygon, and the base about the diameter
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            .
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            Let the figures composed from cones be equal in area.
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            I say that: the cone = the solid figures composed from the said conical ]</s>
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          <p xml:lang="lat">
            <s xml:space="preserve"> Ita similiter in altero
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            hemisphærio:
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            cum tot residuis conorum supra dictis = tot et talibus conis æqualibus supra
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            [
              <emph style="bf">Translation: </emph>
            Thus similarly in the other hemisphere.
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            since all the remaining above said cones = as many and the same equal cones as above ]</s>
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          <p xml:lang="lat">
            <s xml:space="preserve"> Sed omnium conorum altitudines sunt æquales, nempe
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            .
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            et aggregatum ex omnnibus basibus = superficie figuræ compositæ
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            ex conicis.
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            Ergo: […] = solidæ figuræ coprehensæ a dictis conicis
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            superficiebus.
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            Quod fuit
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            [
              <emph style="bf">Translation: </emph>
            But all the altitudes of the cones are equal, namely, to
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            ;
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            and the sum of all the bases = the surface of the figure composed from cones.
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            Therefore = the solid figure composed of the said cones.
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            Whcih was to be ]</s>
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