Harriot, Thomas, Mss. 6784

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page |< < (249) of 862 > >|
    <echo version="1.0RC">
      <text xml:lang="eng" type="free">
        <div type="section" level="1" n="1">
          <pb file="add_6784_f249" o="249" n="497"/>
          <div type="page_commentary" level="0" n="0">
            <p>
              <s xml:space="preserve">[
                <emph style="bf">Commentary:</emph>
              </s>
            </p>
            <p>
              <s xml:space="preserve"> The problem pursued in this and many other folios in Add MS 6784 is that of 'inclination' or 'neusis', as set out in Pappus,
                <emph style="it">Mathematicae collectiones</emph>
                <ref id="pappus_1588"> (Pappus </ref>
              , Book 7. For a statement of the problem see Add MS 6784
                <ref target="http://echo.mpiwg-berlin.mpg.de/ECHOdocuView?url=/permanent/library/XT0KZ8QC/&start=580&viewMode=image&pn=581"> f. </ref>
              . </s>
              <s xml:space="preserve">]</s>
            </p>
          </div>
          <head xml:space="preserve" xml:lang="lat"> 1.) De
            <lb/>
          [
            <emph style="bf">Translation: </emph>
          On ]</head>
          <p xml:lang="lat">
            <s xml:space="preserve"> Ducere lineam
              <math>
                <mstyle>
                  <mi>a</mi>
                  <mi>t</mi>
                  <mi>s</mi>
                </mstyle>
              </math>
              <lb/>
            ut sit:
              <math>
                <mstyle>
                  <mi>e</mi>
                  <mi>s</mi>
                  <mo>=</mo>
                  <mi>s</mi>
                  <mi>b</mi>
                </mstyle>
              </math>
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            To draw a line
              <math>
                <mstyle>
                  <mi>A</mi>
                  <mi>T</mi>
                  <mi>S</mi>
                </mstyle>
              </math>
            so that
              <math>
                <mstyle>
                  <mi>e</mi>
                  <mi>s</mi>
                  <mo>=</mo>
                  <mi>e</mi>
                  <mi>b</mi>
                </mstyle>
              </math>
            . </s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> Desideratur
              <lb/>
            apud Alhazen
              <lb/>
            pag. 140.
              <lb/>
            et aliud. 136. pag.
              <lb/>
            Solvitur
              <lb/>
            in [???]
              <lb/>
            4
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Needed in Alhazen page 140 and also page 136.
              <lb/>
            Solved in [???] 4 sheets. ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> Modus solvendi hoc problema
              <lb/>
            maxime adcommodus est
              <lb/>
            per elementa
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            The most convenient method of solving this problem is by the elements of ]</s>
          </p>
          <p xml:lang="lat">
            <s xml:space="preserve"> Intelligatur (
              <math>
                <mstyle>
                  <mi>a</mi>
                </mstyle>
              </math>
            ) rectus. et visibile in
              <lb/>
            linea (
              <math>
                <mstyle>
                  <mi>b</mi>
                </mstyle>
              </math>
            ) sed infinita distantia:
              <lb/>
            Tum quærendum est punctum
              <lb/>
            reflexionis quod erit in (
              <math>
                <mstyle>
                  <mi>e</mi>
                </mstyle>
              </math>
            )
              <lb/>
            et ducatur (
              <math>
                <mstyle>
                  <mi>a</mi>
                  <mi>e</mi>
                  <mi>s</mi>
                </mstyle>
              </math>
            )
              <lb/>
            unde problema solvitur ut
              <lb/>
            in Chartis elimenti
              <lb/>
            reflexionis
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            It is to be understood that
              <math>
                <mstyle>
                  <mi>a</mi>
                </mstyle>
              </math>
            is a line, and visible in the line
              <math>
                <mstyle>
                  <mi>b</mi>
                </mstyle>
              </math>
            but infnitely distant.
              <lb/>
            Then there is sought the point of reflection which will be
              <math>
                <mstyle>
                  <mi>e</mi>
                </mstyle>
              </math>
            , and
              <math>
                <mstyle>
                  <mi>a</mi>
                  <mi>e</mi>
                  <mi>s</mi>
                </mstyle>
              </math>
            is drawn, whence the problem is solved as it is in the sheets on the elements of reflection. </s>
          </p>
        </div>
      </text>
    </echo>
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