<s xml:space="preserve">
The problem pursued in this and many other folios in Add MS 6784 is 'the cutting-off of an area',
as set out in Pappus,
<emph style="it">Mathematicae collectiones</emph>
<ref id="pappus_1588">
(Pappus </ref>
, Book 7. For a statement of the problem see Add MS 6784
<ref target="http://echo.mpiwg-berlin.mpg.de/ECHOdocuView?url=/permanent/library/XT0KZ8QC/&start=30&viewMode=image&pn=37">
f. </ref>
. </s>
<s xml:space="preserve">]</s>
</p>
</div>
<head xml:space="preserve" xml:lang="lat">
1. problematis de spatij resectione 4
<emph style="super">a</emph>
demonstratione et
<lb/>
[
<emph style="bf">Translation: </emph>
Problems of cutting off of an area, demonstration and most ]</head>
<p xml:lang="lat">
<s xml:space="preserve">
Quatuor possunt esse
<lb/>
resectiones ab uno
<lb/>
puncto dato et duabus
<lb/>
solummodo lineis datis;
<lb/>
secundum quantitatem
<lb/>
spatij dati
<lb/>
aliquando tres:
<lb/>
semper
<lb/>
[
<emph style="bf">Translation: </emph>
There are four possible sections from one given point and just two given lines,
according to the size of the given area; sometimes three, always two.</s>
</p>
<p xml:lang="lat">
<s xml:space="preserve">
Exegesis.
<lb/>
producetur
<math>
<mstyle>
<mi>A</mi>
<mi>C</mi>
</mstyle>
</math>
usque ad
<math>
<mstyle>
<mi>L</mi>
</mstyle>
</math>
et fiat
<lb/>
<math>
<mstyle>
<mi>C</mi>
<mi>L</mi>
</mstyle>
</math>
æqualis
<math>
<mstyle>
<mi>D</mi>
<mi>E</mi>
</mstyle>
</math>
cui etiam sit æqualis
<lb/>
sit
<math>
<mstyle>
<mi>A</mi>
<mi>M</mi>
</mstyle>
</math>
. Around
<math>
<mstyle>
<mi>M</mi>
</mstyle>
</math>
intervallo
<math>
<mstyle>
<mi>A</mi>
<mi>L</mi>
</mstyle>
</math>
<lb/>
agatur periferia
<math>
<mstyle>
<mi>F</mi>
<mi>Z</mi>
<mi>O</mi>
</mstyle>
</math>
.
<lb/>
Ab
<math>
<mstyle>
<mi>E</mi>
</mstyle>
</math>
puncto, per
<math>
<mstyle>
<mi>O</mi>
</mstyle>
</math>
et
<math>
<mstyle>
<mi>F</mi>
</mstyle>
</math>
Ducatur rectæ
<lb/>
<math>
<mstyle>
<mi>E</mi>
<mi>F</mi>
</mstyle>
</math>
et
<math>
<mstyle>
<mi>E</mi>
<mi>W</mi>
</mstyle>
</math>
.
<lb/>
Dico
<lb/>
[
<emph style="bf">Translation: </emph>
Exegesis.
<lb/>
Let
<math>
<mstyle>
<mi>A</mi>
<mi>C</mi>
</mstyle>
</math>
be extended as far as
<math>
<mstyle>
<mi>L</mi>
</mstyle>
</math>
and make
<math>
<mstyle>
<mi>C</mi>
<mi>L</mi>
</mstyle>
</math>
equal to
<math>
<mstyle>
<mi>D</mi>
<mi>E</mi>
</mstyle>
</math>
to which
<math>
<mstyle>
<mi>A</mi>
<mi>M</mi>
</mstyle>
</math>
is also equal. Around
<math>
<mstyle>
<mi>M</mi>
</mstyle>
</math>
with radius
<math>
<mstyle>
<mi>A</mi>
<mi>L</mi>
</mstyle>
</math>
there is constructed the circumference
<math>
<mstyle>
<mi>F</mi>
<mi>Z</mi>
<mi>O</mi>
</mstyle>
</math>
. From the point
<math>
<mstyle>
<mi>E</mi>
</mstyle>
</math>
, through
<math>
<mstyle>
<mi>O</mi>
</mstyle>
</math>
and
<math>
<mstyle>
<mi>F</mi>
</mstyle>
</math>
there are drawn the lines
<math>
<mstyle>
<mi>E</mi>
<mi>F</mi>
</mstyle>
</math>
and
<math>
<mstyle>
<mi>E</mi>
<mi>W</mi>
</mstyle>
</math>
.
<lb/>
I say ]</s>
</p>
<p xml:lang="lat">
<s xml:space="preserve">
Poristice et inde
<lb/>
synthesis manifesta
The poristic, and hence the synthesis, is obvious.</s>