Harriot, Thomas, Mss. 6784

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375188
[Commentary:
The problem pursued in this and the seven following folios is 'on tangencies', as set out in Pappus, Mathematicae collectiones, Book 7. In Commandino's edition of 1588 (Pappus , the problem is stated on page 159–159v.
Punctis, & rectis lineis, & circulis quibuscumque duobus datis circulum describere magnitudine datum, qui per datum punctum, vel data puncta transeat; contingat autem vnamquamque datarum
Given any two points, lines, or circles in position, to draw a circle of a given size, which passes through any given point or points and touches any of the given lines.]
1.) Ad locum de tactibus (.
[Translation: On the place of ]
De parabola.
[Translation: On the parabola. ]
Sit curvum bdl parabola.
cuius axis ba, producta.
recta, bx.
fiat, ba=bx4.
et sit quælibet linea ordinatim
applicata cd.
agatur ad.
Dico quod: ab+bc=ad
[Translation: Let the curve bdl be a parabola, with axis ba extended, bx a straight line.
Make ba=bx4 and let cd be any ordinate. Construct ad. I say that ab+bc=ad.
Corollarium. 1m.
Hinc patet quod curva parabolæ
bdl, est locus centrorum omnium
circulorum qui possunt contingere
lineam ot, et punctum a.
Huiusmodi punctum a in variis
scriptis nostris, usurpandimus
appellate, parabolæ
[Translation: Corollary 1.
Here it is clear that the parabolic curve bdl is the locus of the centres of all the circles that can touch the line ot and the point a.
In this way, the point a, in my various writings, I may call the centroid of the parabola.
Corollarium. 2m.
Patet etiam pro descriptione
parabolæ: si ab dividatur in partes
æquales, et continuentur in producta
erit prima centrali æqualis numero
ab+1. 2a centralis ab+2.
3a centralis ab+3. &c.
ut si ab dividatur in 3 partes
æquales, erit ad prima centralis
3 + 1, hoc est 4. af, 5. ag, 6. ai, 7
al, 8. &
[Translation: Corollary 2.
The description of the parabola is also clear. If ab is divided into equal parts and they are continued in extension, the first from the centre will be equal in numbers to ab+1, the second from the centre to ab+2, the third to ab+3, etc. so if ab is divided into 3 equal parts, the first from the centre will be 3 + 1, that is, 4, af=5, ag=6, ai=7, al=8, etc.
Corollarium. 3m.
Sit aot angulus rectus et ab=1
et sit ef parallela ot. fiat bm=be.
centro a, et intervallo, am
agatur periferia, et secabit
ef in puncto f
agatur fq perpendic: ot.
Dico quod: fq=fa
Et punctum f est in
parabola. Ut patet
ex
[Translation: Corollary 3.
Let aot be a right angle and ab=1, and let ef be parallel to of. Make bm=be.
With centre a and radius am construct a circumference, and it willl cut ef at the point f. Construct fq perpendicular to ot.
I say that fq=fa. And the point f is on the parabola. As is clear from the suppositions.

[Translation: turn ]

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