Harriot, Thomas, Mss. 6784

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467234
De
[Translation: On ]
A puncto extra circulum
ducere lineam secantem:
ut partes, exterior et
interior, sint in ratione

[Translation: From a point outside a circle draw a line cutting it, so that the external and internal parts are in a given ]
Sit (a) punctum datum, extra
circulum bcd cuius centrum e.
et per e centrum agatur recta
infinita ah quæ secabit
periferium circuli dati in punctis
b, k. et fiat kh æqualis ab
[Translation: Let a be the given point outside the circle bcd whose centre is e, and through the centre e there is constructed an infinite line ah which cuts the circumference of the given circle at the points b and k; and make kh equal to ab.
Sit ratio data ut pq ad qr.
oportet a puncto a ducere
rectum secantem, nempe ad
ut pars exterior ac ad partem
interiorem cd, sit ut pq ad qr
[Translation: Let the given ratio be as paq to qr.
It is required to draw a cutting line from the point a, namely ad so that the external part ac to the internal part cd is as pq to qr.
producatur pr, et fiat rs æqualis pq.
Deinde secetur ah in puncto f ut
af ad fh sit ut pq ad qs. et fiat hg æqualis fa. Inde fit
ut partes af, fg, gh; sint in ratione pq, qr, rs
[Translation: Extend pr and make rs equal to pq.
Then ah is cut at point f so that af to fh is as pq to qs, and make hg equal to fa. Thence the parts af, fg, gh will be in the ratio pq, qr, rs.
Porro super ag fiat circulus adg super diametrum ag. quæ
secabit circulum datum in puncto d. Et agatur recta ad, quæ
secabitur a circulo dato in puncto c.
Dico quod ratio ac ad cd, est ut pq ad qr
[Translation: Then make the circle adg with diameter ag, whcih will cut the given circle at the point d. And construct the line ad, which will be cut by the given circle at the point c.
I say that the ratio ac to cd is as pq to qr.
Centro e intervallo ea, fiat circulus aih. Continuetur ad ad i.
et connectantur i, h, puncta. [???] d, g, et c, f. Quoniam anguli
ad i et d sunt recti (sunt enim in semicirculos.) ih et dg sunt
parallelæ. Et inde triangula aih et adg sunt similia. Quare ut ai
ad ah, sic ad ad ag etiam di ad gh. Et quoniamm ab et kh sunt æqualis
per constructionem, ob parallelismum circulorum bdk, et aih, erunt ac
et di etiam æquales. Sed af etiam æqualis est gh. Igitur ut ad ad ag
ita ac ad af, etiam cd ad fg. Quare etiam alterne ut ac ad cd
ita af ad fg. Sed ut af ad fg ita pq ad qr supra per constructionem.
Ergo ac ad cd est ut pq ad qr. Factum est igitur quod
[Translation: With centre e and radius ea make the circle aih. Extend ad to i and connect the points i, h. [???] d, g, and c, f. Since the angles at i and d are straight lines (for they are in a semicircle) ih and dg are paralle. And hence the triangles aih and adg are similar. Whence as ai to ah, so are ad to ag and also di to gh. And since ab and kh are equal by construction, on account of the parallelism of the circles bdk and aih, the lines ac and di are also equal. But af is also equal to gh. Therefore as ad is to ag so is ac to af and cd to fg. Whence also, alternatively, as ac is to cd, so is af to fg. But as af is to fg so is pq to qr above by construction. Therefore ac to cd is as pq to qr. Therefore it is done as was required.
Corollarium.
Patet quod angulus acf est rectus et in semicirculo cuius
diameter af
[Translation: Corollary
It is clear that the angle acf is a right angle in a semicircle whose diameter is af.

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