Commandino, Federico, Liber de centro gravitatis solidorum, 1565

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      <text>
        <body>
          <chap>
            <p type="main">
              <s id="s.000189">
                <pb pagenum="7" xlink:href="023/01/021.jpg"/>
              metrum habens ed. </s>
              <s id="s.000190">Quoniam igitur circuli uel ellipſis
                <lb/>
              aecb grauitatis centrum eſt in diametro be, & portio­
                <lb/>
              nis aec centrum in linea ed: reliquæ portionis, uidelicet
                <lb/>
              abc centrum grauitatis in ipſa bd conſiſtat neceſſe eſt, ex
                <lb/>
              octaua propoſitione eiuſdem.</s>
            </p>
            <p type="head">
              <s id="s.000191">THEOREMA V. PROPOSITIO V.</s>
            </p>
            <p type="main">
              <s id="s.000192">SI priſma ſecetur plano oppoſitis planis æqui
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              diſtante, ſectio erit figura æqualis & ſimilis ei,
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              quæ eſt oppoſitorum planorum, centrum graui
                <lb/>
              tatis in axe habens.</s>
            </p>
            <p type="main">
              <s id="s.000193">Sit priſma, in quo plana oppoſita ſint triangula abc,
                <lb/>
              def; axis gh: & ſecetur plano iam dictis planis
                <expan abbr="æquidiſtã">æquidiſtan</expan>
                <lb/>
              te; quod faciat ſectionem klm; & axi in
                <expan abbr="pũcto">puncto</expan>
              n occurrat. </s>
              <lb/>
              <s id="s.000194">Dico klm triangulum æquale eſſe, & ſimile triangulis abc
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              def; atque eius grauitatis centrum eſſe punctum n. </s>
              <s id="s.000195">Quo­
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                <figure id="id.023.01.021.1.jpg" xlink:href="023/01/021/1.jpg" number="14"/>
                <lb/>
              niam enim plana abc
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              Klm æquidiſtantia
                <expan abbr="ſecã">ſecan</expan>
                <lb/>
                <arrow.to.target n="marg24"/>
                <lb/>
              tur a plano ae; rectæ li­
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              neæ ab, Kl, quæ ſunt ip
                <lb/>
              ſorum
                <expan abbr="cõmunes">communes</expan>
              ſectio­
                <lb/>
              nes inter ſe ſe æquidi­
                <lb/>
              ſtant. </s>
              <s id="s.000196">Sed æquidiſtant
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              ad, be; cum ae ſit para
                <lb/>
              lelogrammum, ex priſ­
                <lb/>
              matis diffinitione. </s>
              <s id="s.000197">ergo
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              & al
                <expan abbr="parallelogrammũ">parallelogrammum</expan>
                <lb/>
              erit; & propterea linea
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                <arrow.to.target n="marg25"/>
                <lb/>
              kl, ipſi ab æqualis. </s>
              <s id="s.000198">Si­
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              militer demonſtrabitur
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              lm æquidiſtans, & æqua
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              lis bc; & mk ipſi ca.</s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>