Fabri, Honoré
,
Tractatus physicus de motu locali
,
1646
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026/01/470.jpg
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Theorema
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33.
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Si voluatur prædictum planum circa baſim eo modo, quo dictum eſt Th.
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12.
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funependulum iſochronum continet
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1/2
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eiuſdem axis
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; quod eodem modo de
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monſtratur per Th.12. </
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Corollarium.
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<
s
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">Colligo primò, cuilibet ſectori funependulum iſochronum poſſe aſſi
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gnari, quia cuiuſlibet ſectoris, qui voluitur circa angulum, eo modo
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quo diximus Th.13. centrum percuſſionis determinatum eſt. </
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<
s
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">Colligo ſecundò, ſi rotetur planum circulare, eo modo quo diximus
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Th.21. funependuli iſochroni longitudinem continere 2/3 diametri eiuſ
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dem circuli, quia ibi eſt centrum percuſſionis eiuſdem circuli, per
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Th. 21. </
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<
s
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">Colligo tertiò, ſi rotetur planum circulare circa diametrum, etiam
<
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poſſe determinari ex centro percuſſionis inuento, longitudinem fune
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penduli iſochroni, vt patet ex dictis. </
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Theorema
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34.
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Quando voluitur planum triangulare parallelum plano in quo voluitur,
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determinari poteſt longitudo funependuli iſochroni
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; ſit enim AFH, cuius
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centrum extrinſecum percuſſionis fit C, longitudo funependuli iſochro
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ni erit AC, quod eodem modo demonſtratur. </
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Corollarium.
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id
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<
s
id
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">Colligo primò, etiam determinari poſſe, quando ita voluitur vt latus
<
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in quo fit percuſſio ſuſtineat angulum rectum, v.g. triangulum AGB
<
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circumactum circa A, habet centrum percuſſionis in M; igitur AM eſt
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longitudo funependuli iſochroni. </
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s
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">Secundò, ſi voluatur circa angulum rectum; </
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<
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id
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">v.g. triangulum ABH
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circa B, centrum percuſſionis eſt in E; igitur BE eſt longitudo funepen
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duli iſochroni. </
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<
s
id
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">Tertiò, aliquando longitudo prædicta eſt minor latere, in quo fit
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percuſſio, vt patet in exemplis adductis; </
s
>
<
s
id
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N2A4CE
">aliquando eſt æqualis, vt in
<
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triangulo ABD volutum circa A, nam centrum percuſſionis eſt D; </
s
>
<
s
id
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">igi
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tur longitudo funependuli iſochroni eſt AD; </
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<
s
id
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">aliquando eſt maior, vt
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videre eſt in triangulo ALG, quod voluitur circa A; nam longitudo fu
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nependuli iſochroni eſt AI, quæ eſt maior AL. </
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type
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<
s
id
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">Quartò, ſi coniungantur duo triangula v.g. EAS. ADS. voluan
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turque ſimul circa A, eo modo quo diximus ſcilicet parallela plano, in
<
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quo voluuntur, longitudo iſochroni funependuli erit AF, poſito quòd
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F ſit centrum percuſſionis, vt dictum eſt ſuprà Corol. 5. Th.19. </
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</
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id
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type
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">
<
s
id
="
N2A4F4
">Quintò, hinc vides rationem egregij experimenti, quod ſæpè Doctus
<
lb
/>
Merſennus propoſuit, ſcilicet longitudinem funependuli iſochroni eſſe
<
lb
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ferè quadruplam perpendicularis ductæ in baſim trianguli Iſoſcelis, li
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brati circa angulum verticis 150.grad. </
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>
<
s
id
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N2A4FD
">quod certè ad veritatem tam pro
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pè accedit ex geometrica calculatione, vt nullum prorſus diſcrimen </
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