Heron Alexandrinus, Mechanicorum Fragmenta, 1899

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    <archimedes>
      <text>
        <body>
          <chap n="1">
            <p n="1">
              <s id="id.000020">
                <pb pagenum="266"/>
                <lb n="70"/>
              ἐπιστρέψει τὸν κοχλίαν καὶ τὸ ΧΨ τύμπανον, ὥστε
                <lb n="71"/>
              καὶ τὸ ΥΦ συμφυὲς αὐτῷ. </s>
              <s id="id.000021">διὰ δὲ τοῦτο καὶ τὸ παρα­
                <lb n="72"/>
              κείμενον τὸ ΣΤ ἐπιστραφήσεται καὶ τὸ συμφυὲς αὐτῷ
                <lb n="73"/>
                <lb n=""/>
                <lb n=""/>
              τὸ ΠΡ καὶ τὸ τούτῳ παρακείμενον τὸ ΞΟ καὶ τὸ
                <lb n="74"/>
              τούτῳ συμφυὲς τὸ ΜΝ καὶ τὸ τούτῳ παρακείμενον τὸ
                <lb n="75"/>
              ΗΘ, ὥστε καὶ ὁ τούτῳ συμφυὴς ἄξων ὁ ΕΖ, περὶ ὃν
                <lb n="76"/>
              ἐπειλούμενα τὰ ἐκ τοῦ φορτίου ὅπλα κινήσει τὸ βά­
                <lb n="77"/>
              ρος. </s>
              <s id="id.000022">ὅτι γὰρ κινήσει, πρόδηλον ἐκ τοῦ προστεθῆναι
                <lb n="78"/>
              ἑτέραν δύναμιν [2τὴν]2 τῆς χειρολάβης, ἥτις περιγράφει
                <lb n="79"/>
              κύκλον τῆς τοῦ κοχλίου περιμέτρου μείζονα. </s>
              <s id="id.000023">ἀπεδείχθη
                <lb n="80"/>
              γὰρ ὅτι οἱ μείζονες κύκλοι τῶν ἐλασσόνων κατακρατοῦ­
                <lb n="81"/>
              σιν, ὅταν περὶ τὸ αὐτὸ κέντρον κυλίωνται.
                <lb n="82"/>
              </s>
            </p>
            <p n="11">
              <s id="id.000024">Κατὰ δὲ τοὺς περὶ τὸν Ἥρωνα πῶς ἔστιν δυνα­
                <lb n="1"/>
              τὸν δύο δοθεισῶν εὐθειῶν δύο μέσας ἀνάλογον λαβεῖν
                <lb n="2"/>
              ὀργανικῶς, δείξομεν, ἐπειδήπερ ἐστὶν τὸ πρόβλημα
                <lb n="3"/>
              τοῦτο, καθά φησιν καὶ ὁ Ἥρων, στερεόν. </s>
              <s id="id.000025">ἐκθησόμεθα </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>