DelMonte, Guidubaldo, In duos Archimedis aequeponderantium libros Paraphrasis : scholijs illustrata

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    <archimedes>
      <text>
        <body>
          <chap id="N10019">
            <pb xlink:href="077/01/118.jpg" pagenum="114"/>
            <p id="N1458D" type="margin">
              <s id="N1458F">
                <margin.target id="marg189"/>
              34.
                <emph type="italics"/>
              primi
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N14598" type="margin">
              <s id="N1459A">
                <margin.target id="marg190"/>
              29.
                <emph type="italics"/>
              primi
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N145A3" type="margin">
              <s id="N145A5">
                <margin.target id="marg191"/>
              15.
                <emph type="italics"/>
              primi
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.077.01.118.1.jpg" xlink:href="077/01/118/1.jpg" number="76"/>
            <p id="N145B2" type="main">
              <s id="N145B4">Hoc idem multis alijs figuris accidet, vt pentagonis, he
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              gonisæquiangulis, & æquilateris, & alijs. </s>
            </p>
            <p id="N145B8" type="head">
              <s id="N145BA">PROPOSITIO.</s>
            </p>
            <p id="N145BC" type="main">
              <s id="N145BE">Figura dari poteſt, quæ per centrum grauitatis recta li
                <lb/>
              diuiſa, non ſemper in partes diuidatur ęquales. </s>
            </p>
            <p id="N145C2" type="main">
              <s id="N145C4">Habeat triangulum ABC
                <lb/>
                <arrow.to.target n="fig58"/>
                <lb/>
              latera AB AC æqualia. </s>
              <s id="N145CD">trian
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              guliverò centrum grauitatis ſit
                <lb/>
              D. à quo ipſi BC ęquidiſtans
                <lb/>
              Ducatur FDG. Dico partem
                <lb/>
              AFG
                <expan abbr="minorẽ">minorem</expan>
              eſſe parte BFGC.
                <lb/>
              ducatur ADE, quæ bifariam
                <lb/>
                <arrow.to.target n="marg192"/>
              BC diuidet. </s>
              <s id="N145E3">& à puncto G
                <lb/>
              ipſi AE ęquidiſtans ducatur
                <lb/>
              HGK. compleantur〈que〉 figurę
                <lb/>
              EH KF. Quoniam enim FG
                <lb/>
                <arrow.to.target n="marg193"/>
              ęquidiſtans eſt ipſi BC, erit FD ad DG, vt BE ad E
                <gap/>
                <lb/>
              & eſt BE ipſi EC æqualis. </s>
              <s id="N145F4">erit igitur FD ipſi DG ęqua
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              vt etiam paulò ante 15. huius oſtendimus. </s>
              <s id="N145F8">quare FG ip
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              DG dupla. </s>
              <s id="N145FC">eſt. </s>
              <s id="N145FE">ac propterea
                <expan abbr="parallelogrãmum">parallelogrammum</expan>
              FK dupi
                <lb/>
              eſt parallelogrammi DK. quia verò AD ipſius DE du
                <lb/>
              exiſtit, erit quoquè parallelogrammum DH ipſius DK
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              plum. </s>
              <s id="N1460A">Quare DH ipſi FK eſt æquale. </s>
              <s id="N1460C">At verò quoni
                <lb/>
                <arrow.to.target n="marg194"/>
              FG dupla eſt ipſius DG. erit triangulum AFG parallelog
                <lb/>
              mo DH æquale. </s>
              <s id="N14616">triangulum igitur AFG parallelog
                <gap/>
                <lb/>
              FK eſt æquale. </s>
              <s id="N1461B">Quare pars AFG parte BFGC minor
                <gap/>
                <lb/>
              ſtit. </s>
              <s id="N14620">quod demonſtrare oportebat. </s>
            </p>
            <p id="N14622" type="margin">
              <s id="N14624">
                <margin.target id="marg192"/>
                <emph type="italics"/>
              ex
                <emph.end type="italics"/>
              13.
                <emph type="italics"/>
              hui'
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N14632" type="margin">
              <s id="N14634">
                <margin.target id="marg193"/>
                <emph type="italics"/>
              lemma an­
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              te
                <expan abbr="ſecundã">ſecundam</expan>
                <lb/>
                <expan abbr="demonſtra-tionẽ">demonſtra­
                  <lb/>
                tionem</expan>
                <emph.end type="italics"/>
              13
                <emph type="italics"/>
              bu
                <lb/>
              ius.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N14650" type="margin">
              <s id="N14652">
                <margin.target id="marg194"/>
                <emph type="italics"/>
              ex
                <emph.end type="italics"/>
              41.
                <emph type="italics"/>
              pri.
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              mi.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.077.01.118.2.jpg" xlink:href="077/01/118/2.jpg" number="77"/>
            <p id="N14666" type="main">
              <s id="N14668">Hinc perſpicuum eſt, eandem figuram per centrum gra
                <lb/>
              tatis diuiſam, aliquando in partes in æquales, aliquando in
                <lb/>
              tes æquales diuidi poſſe. </s>
              <s id="N1466E">in partes inęquales iam oſtenſum
                <lb/>
              hocaccidere
                <expan abbr="perlineã">perlineam</expan>
              FG. in partes verò æquales patet pe
                <lb/>
              neam ADE, quæ triangulum ABC in duo ęqua diuidi
                <gap/>
              . t
                <gap/>
                <lb/>
                <arrow.to.target n="marg195"/>
              gulum enim ABE triangulo: AEC eſt ęquale, cùm ſint
                <gap/>
                <lb/>
              eadem altitudine, baſeſquè BE EC inter ſe ſint æquales. </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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